Question and answer
x + =
Question
Asked 6/27/2013 6:10:02 AM
Updated 7/14/2014 9:53:07 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/14/2014 9:52:46 PM]
Original conversation
User: x + =

Weegy: x times x = x2 (it's like 6 times 6. it would be 62. not 6 times 2. 2x means x times 2) Read more:
wisbest|Points 2627|

User: x + 1/2 = 3/4

Weegy: x+(4)/(x)+2=x+(1)/(x)+5 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is x. [ Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. x+(4)/(x)+2=x*(x)/(x)+(1)/(x)+5*(x)/(x) Multiply x by x to get x^(2). x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+5*(x)/(x) Multiply 5 by x to get 5x. x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+(5x)/(x) Combine the numerators of all expressions that have common denominators. x+(4)/(x)+2=(x^(2)+1+5x)/(x) Reorder the polynomial x^(2)+1+5x alphabetically from left to right, starting with the highest order term. x+(4)/(x)+2=(x^(2)+5x+1)/(x) Find the LCD (least common denominator) of x+(4)/(x)+2+((x^(2)+5x+1))/(x). Least common denominator: x Multiply each term in the equation by x in order to remove all the denominators from the equation. x*x+(4)/(x)*x+2*x=(x^(2)+5x+1)/(x)*x Cancel the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+(4)/( x )* x +2*x=(x^(2)+5x+1)/(x)*x Reduce the expression by removing the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply x by x to get x^(2). x^(2)+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply 4 by 1 to get 4. x^(2)+4+2*x=(x^(2)+5x+1)/(x)*x Multiply 2 by x to get 2x. x^(2)+4+2x=(x^(2)+5x+1)/(x)*x Reorder the polynomial x^(2)+4+2x alphabetically from left to right, starting with the highest order term. x^(2)+2x+4=(x^(2)+5x+1)/(x)*x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1)/( x )* x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1) Remove the parentheses around the expression x^(2)+5x+1. x^(2)+2x+4=x^(2)+5x+1 Since x^(2) contains the variable to solve for, move it to the left-hand side of the equation by subtracting x^(2) from both sides. x^(2)+2x+4-x^(2)=5x+1 Since 5x contains the variable to solve for, move it to the left-hand side of the ]
thederby|Points 1530|

Question
Asked 6/27/2013 6:10:02 AM
Updated 7/14/2014 9:53:07 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/14/2014 9:52:46 PM]
New answers
Rating
3
x + 1/2 = 3/4
x = 3/4 - 1/2
x = 3/4 - 2/4
x = 1/4
Added 7/14/2014 9:53:07 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/16/2014 10:51:57 AM]
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Questions asked by the same visitor
What is the multiplicative inverse of 1/2?
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Expert Answered
Updated 6/20/2014 10:14:37 AM
1 Answer/Comment
The multiplicative inverse of 1/2 is 2.
Added 6/20/2014 10:14:37 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [6/20/2014 10:23:54 AM]
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