How many moles of Ag contain 4.49 x10^23 atoms Ag? a. 0.745 x10^24 mol c. 0.745 mol b. 0.745 x10^23 mol d. 27.0 mol

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1 mole = 6.02 x 10^23; the number of moles of Ag contain 4.49 x10^23 atoms Ag is: (4.49 x 10^23 )/(6.02 x 10^23)= 0.745 mol.

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Asked 12/17/2021 12:55:27 PM

Updated 14 days ago|6/3/2026 1:20:01 PM

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