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Solve by using PEMDAS: 8 x 2 + 9 /3
Question|Rated bad
Asked 11/13/2010 12:43:59 AM
Updated 10/31/2014 6:27:07 PM
0 Answers/Comments
This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [10/31/2014 6:27:06 PM], Confirmed by andrewpallarca [10/31/2014 6:27:07 PM]
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User: Solve by using PEMDAS: 8 x 2 + 9 /3

Weegy: 8 x 2 + 9 /3 = 16 + 9 /3 = 16 + 3 =19
lana1924|Points 5|

User: Solve by using PEMDAS: 6 + 3^2 * 2 / (5 - 2)

Weegy: 6 + 3^2 * 2 / (5 - 2) = 6 + 3^2 * 2 / 3 = 6 + 9 * 2 / 3 = 6 + 18/3 = 6 + 6 = 12
Expert answered|claiie|Points 0|

Question|Rated bad
Asked 11/13/2010 12:43:59 AM
Updated 10/31/2014 6:27:07 PM
0 Answers/Comments
This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [10/31/2014 6:27:06 PM], Confirmed by andrewpallarca [10/31/2014 6:27:07 PM]
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Questions asked by the same visitor
8 x 2 + 9 /3
Weegy: 8 x 2 + 9/3 = 16 + 9/3 = 16 + 3 = 19 (More)
Question
Expert Answered
Updated 10/31/2014 6:25:07 PM
0 Answers/Comments
Simplify: 3(x + 13)
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Updated 6/14/2014 10:37:22 PM
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Multiply (6xy^2)(3x^3y)
Weegy: too complicated (More)
Question
Expert Answered
Updated 7/12/2018 8:34:42 PM
1 Answer/Comment
(6xy^2)(3x^3y) = 18x^4y^3
Added 7/12/2018 8:34:24 PM
This answer has been confirmed as correct and helpful.
Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. What must she score on her 4th test so she will have at least an 85 average?
Question
Updated 1/9/2016 6:54:40 AM
1 Answer/Comment
Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. To have at least an 85 average, she must score at least 91 on her 4th test.
(75+83+91+x)/4=85
249+x=85*4
249+x=340
x=340-249
x=91
Added 1/9/2016 6:54:40 AM
This answer has been confirmed as correct and helpful.
Solve for x: -2x + 4 >10
Question
Not Answered
Updated 10/31/2014 6:24:14 PM
1 Answer/Comment
-2x + 4 >10;
-2x > 10 - 4;
-2x > 6;
x < 6/-2;
x < -3
Added 10/31/2014 6:24:14 PM
This answer has been confirmed as correct and helpful.
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