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9x^3+27x^2-90x
9x³ + 27x² - 90x Take ' 9x ' as HCF = 9x( x² + 3x - 10 ) Find 2 factors of ' - 10 ' whose sum or difference is ' + 3 ' = 9x( x² + 5x - 2x - 10 ) Take ' x ' and ' - 2 ' as HCF = 9x[ x( x + 5 ) - 2( x + 5 ) ] Take ( x + 5 ) as HCF = 9x( x + 5 )( x [ - 2 ) ]
Expert answered|selymi|Points 10116|
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Asked 2/27/2013 8:54:36 AM
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