Find the distance between the points (-3, 2) and (4, -5). v10 7v2 2v2
Question
Updated 7/3/2014 8:31:06 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 8:30:12 PM]
Original conversation
User: Find the distance between the points (-3, 2) and (4, -5). v10 7v2 2v2

Weegy: x^-3/y^-5 = y^5/x^3
Giana|Points 1081|

Question
Updated 7/3/2014 8:31:06 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/3/2014 8:30:12 PM]
Rating
3
The distance between the points (-3, 2) and (4, -5) is sqrt =(4+3)^2+(-5-2)^2] = sqrt (49+49) = sqrt 98 = 7v2
Confirmed by yumdrea [7/4/2014 10:19:07 PM]

Questions asked by the same visitor
Find the product of (5a - 7)(2a - 1)?
Question
Updated 233 days ago|1/28/2018 7:24:33 AM
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 233 days ago|1/28/2018 7:24:33 AM
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
The equation of the circle whose center is at (2, 1) and radius is 3 is
Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9. (More)
Question
Updated 7/3/2014 8:38:35 PM
The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^2 + (y - 1)^2 = 9.
Confirmed by yumdrea [7/4/2014 2:02:51 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Updated 7/3/2014 8:40:00 PM
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
Write the equation of the given circle. center (1, -5) radius of 10
Question
Updated 7/3/2014 8:34:36 PM
The equation of the circle with center (1, -5) radius of 10 is (x - 1)^2 + (y + 5)^2 = 100.
Confirmed by yumdrea [7/4/2014 10:18:40 PM]
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