Simplify: 10x - 2 + 3x
Question
Asked 9/26/2010 1:46:46 PM
Updated 4/30/2014 4:07:54 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/13/2014 8:36:43 AM], Edited by andrewpallarca [4/13/2014 8:36:45 AM]
f
Original conversation
User: Simplify: 10x - 2 + 3x

Weegy: 10x - 2 + 3x = 13x - 2
zch24|Points 6|

User: Simplyfy the following expression: 9(a + 8) - 5 (a - 10)

Question
Asked 9/26/2010 1:46:46 PM
Updated 4/30/2014 4:07:54 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/13/2014 8:36:43 AM], Edited by andrewpallarca [4/13/2014 8:36:45 AM]
Rating
8
9(a + 8) - 5 (a - 10);

9a + 72 - 5a + 50

= 4a + 122
Added 4/30/2014 4:07:54 PM
This answer has been confirmed as correct and helpful.
10x - 2 + 3x = 13x -2

9(a+8) - 5(a-10) = 9a + 72 - 5a + 50 = 4a + 122

Note: Multiplication of the same sign is positive (+).
Added 9/26/2010 3:00:30 PM
Questions asked by the same visitor
Solve:11b - 6 = 10b + 4
Weegy: 11b - 6 = 10b + 4; 11b - 10b = 4 + 6; b = 10 (More)
Question
Updated 4/13/2014 8:35:19 AM
Solve: z - 6.68 = 7.47
Question
Updated 4/13/2014 8:34:42 AM
z=14.15
Added 9/26/2010 1:20:13 PM
z - 6.68 = 7.47;

z = 7.47 + 6.68;

z = 14.15
Added 4/13/2014 8:34:42 AM
This answer has been confirmed as correct and helpful.
Simplify: 10x - 2 + 3x
Weegy: 10x - 2 + 3x = 13x - 2 (More)
Question
Updated 12/1/2014 6:24:23 AM
Add the following: (5x2 + x + 7) + (3x2 - 4x + 3)
Weegy: Did you copy this problem correctly. Are you by chance missing an = sign? (More)
Question
Updated 6/26/2014 6:22:30 PM
(5x^2 + x + 7) + (3x^2 - 4x + 3)

= 5x^2 + 3x^2 + x - 4x + 7 + 3;

= 8x^2 - 3x + 10
Added 6/26/2014 6:22:30 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/26/2014 10:00:16 PM]
Multiply:(5x + 1)(2x - 2)
Weegy: 10x -10x +2x -2 = 2x -2 (More)
Question
Updated 12/1/2014 6:13:31 AM
(5x + 1)(2x - 2)

= 10x^2 - 10x + 2x - 2;

= 10x^2 - 8x - 2
Added 12/1/2014 6:13:31 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [12/1/2014 6:23:50 AM]
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