Question and answer
Working with polynomial: (6x^2 - 25x - 10) / (3x + 2)
(6x^2 - 25x - 10) / (3x + 2) = (6x^2/3x+2) - (25x/3x+2) - (10/3x+2) = 2x - 29/3 R. 28/3
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Asked 12/13/2010 3:54:20 AM
Updated 7/27/2014 12:19:20 PM
1 Answer/Comment
Edited by andrewpallarca [7/27/2014 12:18:08 PM]
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(6x^2 - 25x - 10) / (3x + 2)
= (6x^2/3x+2) - (25x/3x+2) - (10/3x+2)
= 2x - 29/3 R. 28/3
Added 7/27/2014 12:19:20 PM
This answer has been confirmed as correct and helpful.
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Okay here is another one: Simplify (9x²y4)³
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Updated 2/25/2014 1:38:11 AM
1 Answer/Comment
(9x^2y^4)^3 is 729 x^6 y^12.
Added 2/25/2014 1:38:11 AM
This answer has been confirmed as correct and helpful.
Working with polynomial: (5x – 3.6) – (4x + 1.2)
Weegy: x-4.8 User: Please show the steps on how you got this answer. Thanks (More)
Question
Expert Answered
Updated 7/3/2014 1:57:21 PM
1 Answer/Comment
(5x – 3.6) – (4x + 1.2)

= 5x - 3.6 - 4x - 1.2

= 5x - 4x - 3.6 - 1.2

= x - 4.8
Added 7/3/2014 1:57:21 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/3/2014 2:07:02 PM]
Working with polynomial: (3x^2 + 3x) + (4x + 4). Please show the steps on how you got your answer. Thanks!
Question
Not Answered
Updated 8/10/2014 5:55:48 PM
1 Answer/Comment
(3x^2 + 3x) + (4x + 4)

= 3x^2 + 3x + 4x + 4;

= 3x^2 + 7x + 4
Added 8/10/2014 5:55:48 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/10/2014 5:57:18 PM]
Working with polynomials: (2x4 + 3)(4x³+ 2)
Weegy: (2x4 + 3)(4x³+ 2) = 8x^12 + 4x^4 + 12x^3 + 6 (More)
Question
Expert Answered
Updated 7/16/2014 11:07:55 AM
1 Answer/Comment
(2x^4 + 3)(4x^3 + 2) = 8x^7 + 4x^4 + 12x^3 + 6
Added 7/16/2014 11:07:54 AM
This answer has been confirmed as correct and helpful.
Working with polynomial: (12y³ + 8 y² + 20y) / 2y
Weegy: x+2y+z --> x = -2y-z (More)
Question
Expert Answered
Updated 7/16/2014 11:09:47 AM
1 Answer/Comment
(12y³ + 8y² + 20y) / (2y)
= (12y³/2y) + (8y²/2y) + (20y/2y)
= 6y^2 + 4y + 10
Added 7/16/2014 11:09:46 AM
This answer has been confirmed as correct and helpful.
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