Solve the system algebraically. "3x - 2y - 1 = 0," "y = 5x + 4"
3x - 2y - 1 = 0 y = 5x + 4 Use substitution method: 3x - 2(5x + 4) - 1 = 0 3x - 10x - 8 - 1 = 0 -7x - 9 = 0 -7x = 9 x = -9/7 Solve for y: y = 5(-9/7) + 4 y = -45/7 + 4 y = -17/7 Solution set: (-9/7, -17/7)
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Question
Asked 2/3/2013 4:00:21 AM
Updated 8/17/2015 5:08:48 PM
Edited by Andrew. [8/17/2015 5:06:50 PM]
Rating
3
3x - 2y - 1 = 0
y = 5x + 4

Use substitution method:
3x - 2(5x + 4) - 1 = 0
3x - 10x - 8 - 1 = 0
-7x - 9 = 0
-7x = 9
x = -9/7
Solve for y:
y = 5(-9/7) + 4
y = -45/7 + 4
y = -17/7
Solution set: (-9/7, -17/7)
Added 8/17/2015 5:08:48 PM
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