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Place the indicated product in the proper location on the grid. (3m^3 - 1/2y) (3m^3 - 1/2y)
Question
Asked 4/22/2016 3:26:43 PM
Updated 4/25/2016 1:25:52 AM
1 Answer/Comment
Flagged by arel [4/24/2016 10:53:34 PM]
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User: Place the indicated product in the proper location on the grid. (3m^3 - 1/2y) (3m^3 - 1/2y)

Question
Asked 4/22/2016 3:26:43 PM
Updated 4/25/2016 1:25:52 AM
1 Answer/Comment
Flagged by arel [4/24/2016 10:53:34 PM]
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(3m^3 - 1/2y) (3m^3 - 1/2y)
= 3m^3*3m^3 - 1/2y*3m^2 - 3m^3*1/2y + (-1/2y)(-1/2y)
= 9m^6 - 3/2m^3y - 3/2m^3y + 1/4y^2
= 9m^6- 3m^3y + 1/4y^2
Added 4/25/2016 1:25:52 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/25/2016 1:37:48 AM]
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Questions asked by the same visitor
Place the indicated product in the proper location on the grid. Write your answer in descending powers of x. (x^2 + 2x - 1)(x^2 + 2x + 5)
Weegy: (x^2 + 2x - 1)(x^2 + 2x + 5) = x^4 + 2x^3 + 5x^2 + 2x^3 + 4x^2 + 10x - x^2 - 2x - 5; = x^4 + 4x^3 + 8x^2 + 8x - 5 (More)
Question
Updated 4/23/2016 1:53:27 AM
0 Answers/Comments
Place the indicated product in the proper location on the grid. (w^2 x^2) (w^2 x^2 )
Question
Updated 4/24/2016 10:48:53 PM
1 Answer/Comment
(w^2 x^2) (w^2 x^2 )
= w^(2+2)*x^(2+2)
= w^4x^4
Added 4/24/2016 10:48:53 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/24/2016 10:50:42 PM], Rated good by jeifunk
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