multiply (5xy^4)(2x^2y)
Question
Updated 6/16/2014 2:09:43 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/16/2014 2:09:28 PM]
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Original conversation
User: Simplify 6(y + 7)

User: 5x + 7 + 9x - 4

User: multiply (5xy^4)(2x^2y)

Weegy: Do you have more to the equation?
boopydoop1|Points 2229|

Question
Updated 6/16/2014 2:09:43 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/16/2014 2:09:28 PM]
Rating
3
5x + 7 + 9x - 4 = 14x + 3
3
(5xy^4)(2x^2y) = 10x^3y^5

Questions asked by the same visitor
Factor completely: 15x3y2 25x2y2 5xy2
Weegy: Factor completely: 15x3y2 + 25x2y2 + 5xy2 = xy^2( 15x^2 +25x+5) x=0; y=0 double 15x^2 +25x+5=0; 3x^2 +5x+1=0 x=(-5+ root(13))/6 x=(-5- root(13))/6 User: Factor completely: x2 + 8x+ 12 Weegy: x2+8x +15=0 x=(-8+- root(8^2 -4*1*15)) /2 = (-8+-2) /2 x=-6/2=-3 x=-10/2=-5 x2+ 8x +15= ( x + 5 )( x + 3 ) User: Factor completely: 16x2 - 49 User: (4x^2+6x+3)+(2x^2-5x-3) Weegy: Factor by grouping. Your answer is (2x - 3)(x^2 - 2) User: Given the equation if the line 5x+y=10 , find the missing number in the ordered pair (1,?) that represents a point on this line. User: Divide: (5x^3 + 15x - 10x) / 5x Weegy: The quotient of (10x^6 - 15x^5 - 5x^3) and (5x^3) is 2x^3 - 3x^2 - 1. The product of (x^2 - 3x + 5) and (2x^3 - 3x^2 - 1) is 2x^5 -9x^4 +19x^3 -16x^2 + 3x -5. User: Simplify: 3x - { 4y - 2[ 3y - ( 2 - 2y)]} Weegy: 3x - 4y = 30 User: The area of a square is 25 sq meters. What is the perimeter of that square? Weegy: If the area of a squre is 16 sq meters then each side is 4m. that would make the perimeter 16 meters. User: Evaluate" x^2 + 9x +7 when x= -3 User: Solve for x: -4x + 7 = 35 Weegy: The answer is x=-6,2. [ x^(2)-12=-4x Since -4x contains the variable to solve for, move it to the left-hand side of the equation by adding 4x to both sides. x^(2)-12+4x=0 Reorder the polynomial x^(2)-12+4x alphabetically from left to right, starting with the highest order term. x^(2)+4x-12=0 In this problem 6*-2=-12 and 6-2=4, so insert 6 as the right hand term of one factor and -2 as the right-hand term of the other factor. (x+6)(x-2)=0 Set each of the factors of the left-hand side of the equation equal to 0. x+6=0_x-2=0 Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides. x=-6_x-2=0 Set each of the factors of the left-hand side of the equation equal to 0. x=-6_x-2=0 Since -2 does not contain the variable to solve for, move it to the right-hand side of ... (More)
Question
Updated 3/19/2014 11:03:13 PM
3x - { 4y - 2[ 3y - ( 2 - 2y)]}
= 3x - [4y - 2(3y - 2 + 2y)]
= 3x - [4y - 2(5y - 2)]
= 3x - (4y -10y + 4)
= 3x - (-6y + 4)
= 3x + 6y - 4
Confirmed by jeifunk [3/19/2014 11:15:32 PM]
The area of a square is 25 sq meters. Its side is sqrt 25 = 5 meters, so the perimeter of the square = 5*4 = 20 meters.

Confirmed by jeifunk [3/19/2014 11:15:33 PM]
when x= -3,
x^2 + 9x +7
= (-3)^2 + 9(-3) + 7
= 9 - 27 + 7
= - 18 + 7
= - 11
Confirmed by jeifunk [3/19/2014 11:15:34 PM]
-4x + 7 = 35
-4x = 35 - 7 = 28
x = 28/-4 = - 7
Confirmed by jeifunk [3/19/2014 11:15:35 PM]
-2(x - 4) = -3(x + 8)
-2x + 8 = -3x - 24
-2x + 3x = -24 - 8
x = - 32
Confirmed by jeifunk [3/19/2014 11:15:36 PM]
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