Question and answer
Determine the amount of oxygen required to completely combust 15 g of propane.
mass_C3H8 = 15 # g M_C3H8 = 44.1 # g/mol moles_C3H8 = mass_C3H8 / M_C3H8 moles_O2 = moles_C3H8 * 5 # C3H8 + 5 O2 = 3 CO2 + 4 H2O mass_O2 = moles_O2 * 32 moles_C3H8 = 15 / 44.1 moles_O2 = moles_C3H8 * 5 mass_O2 = 54.2 g
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Asked 48 days ago|2/23/2026 7:54:32 AM
Updated 48 days ago|2/23/2026 8:12:11 AM
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mass_C3H8 = 15 # g
M_C3H8 = 44.1 # g/mol
moles_C3H8 = mass_C3H8 / M_C3H8
moles_O2 = moles_C3H8 * 5 # C3H8 + 5 O2 = 3 CO2 + 4 H2O
mass_O2 = moles_O2 * 32
moles_C3H8 = 15 / 44.1
moles_O2 = moles_C3H8 * 5
mass_O2 = 54.2 g
Added 48 days ago|2/23/2026 8:12:11 AM
This answer has been confirmed as correct and helpful.
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Estimate the pH of a 0.05 M acetic acid solution (Ka = 1.8 × 10 ).
Weegy: Given: CH COOH 0.1 M, Ka = 1.8?10 CH COOH H + CH COO Let x = [H ] Ka = x? / (0.1 x) = x? / 0.1 x? = Ka ? 0.1 = 1.8?10 ? 0.1 = 1.8?10 x = (1.8?10 ) = 1.34?10 ? M pH = -log(1.34?10 ?) = 2.87 Answer: pH = 2.87 (More)
Question
Updated 48 days ago|2/23/2026 8:15:08 AM
1 Answer/Comment
C = 0.05
Ka = 1.8e-5
H_conc = (Ka * C)**0.5
pH = -log10(H_conc)
H_conc = (1.8e-5 * 0.05)**0.5
H_conc= 0.0009487
pH = 3.02
Added 48 days ago|2/23/2026 8:15:08 AM
This answer has been confirmed as correct and helpful.
Calculate the theoretical yield of ethanol from 100 g of glucose via fermentation.
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Not Answered
Updated 48 days ago|2/23/2026 8:12:48 AM
1 Answer/Comment
mass_glucose = 100 # g
M_glucose = 180.16 # g/mol
M_ethanol = 46.08 # g/mol
moles_glucose = mass_glucose / M_glucose
moles_ethanol = moles_glucose * 2 # C6H12O6 = 2 C2H5OH + 2 CO2
mass_ethanol = moles_ethanol * M_ethanol
moles_glucose = 100 / 180.16
moles_ethanol = moles_glucose * 2
mass_ethanol = 51.1 g
Added 48 days ago|2/23/2026 8:12:48 AM
This answer has been confirmed as correct and helpful.
Calculate the enthalpy change when 2 mol of H reacts with O to form water.
Weegy: 2H2 + O2 2H2O 2 mol H2 + 1 mol O2 - 2 mol H2O (More)
Question
Updated 48 days ago|2/23/2026 8:14:49 AM
1 Answer/Comment
n_H2 = 2
H_reaction_per_mol = -286 # kJ/mol H2
H_total = n_H2 * H_reaction_per_mol
H_total = 2 * -286
H_total = -572 kJ
Added 48 days ago|2/23/2026 8:14:39 AM
This answer has been confirmed as correct and helpful.
Estimate the percentage yield if 50 g of NH is produced from 100 g of N and H .
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Updated 48 days ago|2/23/2026 8:11:30 AM
1 Answer/Comment
mass_NH3_produced = 50
mass_NH3_theoretical = 100
percentage_yield = (mass_NH3_produced / mass_NH3_theoretical) * 100
percentage_yield = (50 / 100) * 100
percentage_yield = 50%
Added 48 days ago|2/23/2026 8:11:30 AM
This answer has been confirmed as correct and helpful.
Determine the gravitational potential energy of a 5 kg object at 12 m heigh
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Not Answered
Updated 48 days ago|2/23/2026 8:08:36 AM
1 Answer/Comment
m = 5 # kg
g = 9.81 # m/s²
h = 12 # m
PE = m * g * h
PE = 5 * 9.81 * 12
PE = 588.6 J
Added 48 days ago|2/23/2026 8:08:36 AM
This answer has been confirmed as correct and helpful.
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