Solution:
To find the ordered pairs that satisfy the given system of equations:

2/5x + 1/2y = 309/95 ...(Equation 1)
1/2x - 1/6y = 6/19 ...(Equation 2)

10 * (2/5x + 1/2y) = 10 * (309/95)
6 * (1/2x - 1/6y) = 6 * (6/19)
4x + 5y = 618/19
3x - y = 36/19
5 * (3x - y) = 5 * (36/19)
15x - 5y = 180/19
(4x + 5y) + (15x - 5y) = (618/19) + (180/19)
19x = 798/19
x = (798/19) / 19
x = 798/361
x = 2.212

Now, substituting this value of "x" back into Equation 3:
4x + 5y = 618/19
4 * 2.212 + 5y = 618/19
8.848 + 5y = 618/19
5y = (618/19) - 8.848
5y = (618 - (8.848 * 19))/19
5y = 468/19
y = (468/19) / 5
y = 468/95
y = 4.92

Therefore, the ordered pair (x, y) that satisfies the given system of equations is approximately (2.212, 4.92).

The solution for 2x + 3y = 11, -8x + y = 47 is:
x = -5, y = 7
SUBSTITUTION METHOD:
2x + 3y = 11, -8 + y = 47;
Isolate y in eq 2:
y = 8x + 47;
Put the value of y to eq. 1, and solve for x:
2x + 3(8x + 47) = 11;
2x + 24x + 141 = 11;
26x + 141 = 11;
26x = 11 - 141;
26x = -130;
x = -130/26;
x = -5;
Put x = -5 to any equation, and solve for y:
2(-5) + 3y = 11;
-10 + 3y = 11;
3y = 11 + 10;
3y = 21;
y = 21/3;
y = 7