Weegy: Factor each polynomial
12x^2-5x-3 = (4x - 3)(3x + 1),
checking our factoring using FOIL
F First terms 12x^2
O Outside terms +4x
I Inside terms -9x
L Last terms -3
Expert answered|aarongrutas|Points 10|

User: use the difference of two squares formula to factor. Be sure to factor out any common factors. y^2-49

Weegy: y^2 - 49, next step is = y^2 - 7^2, and the last is = (y+7) (y-7). [smile] Expert answered|aarongrutas|Points 10|

User: use the difference of two squares formula to factor. Be sure to factor out any common factors. 4x^2-25

Weegy: Yeah, I will be sure, so The problem is (2x)^ 2 - 5^2 Then it will be (2x+5) (2x-5). Expert answered|aarongrutas|Points 10|

User: use the difference of two squares formula to factor. Be sure to factor out any common factors. 81x^2-1

Weegy: So this is the problem, 81x^2-1
, Then the factor is (9x - 1)(9x + 1). Expert answered|aarongrutas|Points 10|

User: Using the perfect square trinomial formulas to factor. Be sure to factor out any common factors. 16y^2-8y+1

Weegy: The answer is (4X-1)^2. Expert answered|aarongrutas|Points 10|

User: find all the roots and check your answers. x^2+5x-14=0

Weegy: Ok so this is the solution 1. x^2+5x-14=0 2.x^2+7x-2x-14=0 3.x(x+7)-2(x+7)=0 4.(x+7)(x-2)=0, Then the answer is x=-7 OR 2. Expert answered|aarongrutas|Points 10|

User: find all the roots and check your answers. 3x^2+5x=0

Weegy: Here is the solution: 3x^2+5x=0
next is x(3x+5)=0
then the answer is x=0 OR x= -5/3 Expert answered|aarongrutas|Points 10|

User: find all the roots and check your answers. 49x^2-25=0

Weegy: Start with the given expression
%28x%5E3%2B8x%5E2%29%2B%282x%2B16%29 Group like terms
x%5E2%28x%2B8%29%2B2%28x%2B8%29 Factor out the GCF x%5E2 out of the first group. [ Factor out the GCF 2 out of the second group
%28x%5E2%2B2%29%28x%2B8%29 Since we have the common term x%2B8, we can combine like terms
So x%5E3%2B8x%5E2%2B2x%2B16 factors to %28x%5E2%2B2%29%28x%2B8%29
In other words, x%5E3%2B8x%5E2%2B2x%2B16=%28x%5E2%2B2%29%28x%2B8%29
] (More)

There are no comments.