A 2 kg mass is accelerated from rest to 12 m/s in 6 seconds.

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a = (v-u)/t = 12/6 = 2 m/s² F = ma = 2 × 2 = 4 N

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Asked 75 days ago|1/27/2026 6:46:09 AM

Updated 75 days ago|1/27/2026 7:08:35 AM

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cruz30

a = (v-u)/t = 12/6 = 2 m/s²
F = ma = 2 × 2 = 4 N

Added 75 days ago|1/27/2026 7:08:35 AM

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A 5 kg block slides 10 m with friction force 20 N. Work done by friction?

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Updated 76 days ago|1/26/2026 8:38:23 AM

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cruz30

W = Fd cos(180) = 20(10)(-1) = -200 J

Added 76 days ago|1/26/2026 8:38:21 AM

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Updated 76 days ago|1/26/2026 8:37:55 AM

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cruz30

F = ma
a = F/m = 10/2 = 5 m/s^2

Added 76 days ago|1/26/2026 8:37:55 AM

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A 0.2 kg ball is thrown at 15 m/s. Find momentum.

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Updated 76 days ago|1/26/2026 8:46:09 AM

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cruz30

p = mv = 0.2 × 15 = 3 kg·m/s

Added 76 days ago|1/26/2026 8:45:53 AM

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Flora1988

Momentum = mass × velocity = 0.2 kg × 15 m/s = 3 kg m/s.

Added 76 days ago|1/26/2026 8:46:09 AM

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A 2 kg object at 10 m height. Potential energy?

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Updated 76 days ago|1/26/2026 8:45:20 AM

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cruz30

PE = mgh = 2(9.8)(10) = 196 J

Added 76 days ago|1/26/2026 8:45:20 AM

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A 50 W bulb works for 2 hours. Energy used?

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Updated 76 days ago|1/26/2026 8:45:04 AM

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cruz30

E = Pt = 50 × (2×3600) = 360000 J

Added 76 days ago|1/26/2026 8:45:04 AM

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