Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20. A. x = 10, y = 20 C. x = 2, y = 12 B. x = –10, y = 20 D. x = –6, y = 4
Updated 4/8/2014 6:55:26 AM
Confirmed by jeifunk [4/8/2014 6:55:26 AM]
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Original conversation
User: Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20. A. x = 10, y = 20 C. x = 2, y = 12 B. x = –10, y = 20 D. x = –6, y = 4

Weegy: 2x + 3y = 40
2x + 2y = 20
Adding two equations we get 5y = 60
y = 60/5 = 12
2x + 3(12) = 40
2x = 40 - 36 = 4
x = 2
Thus, the solution for the system of equations 2x + 3y = 40 and 2x + 2y = 20 is C. x = 2, y = 12

User: Solve the system of equations 2r + 2s = 50 and 2r – s = 17. A. r = 14, s = 11 C. r = 25, s = 33 B. r = 3, s = 11 D. r = –8, s = 33

Updated 4/8/2014 6:55:26 AM
Confirmed by jeifunk [4/8/2014 6:55:26 AM]
Rating
3
2r + 2s = 50 divided by 2 on both sides: r + s = 25 (equation 1)
2r – s = 17 (equation 2)
Add up equation 1 and 2 we get; 3r = 42, r = 42/3 = 14
2(14) - s = 17
s = 28 - 17 = 11
The solution for the system of equations 2r + 2s = 50 and 2r – s = 17 is A. r = 14, s = 11.
Confirmed by jeifunk [4/8/2014 6:54:02 AM]

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Weegy: To start a program from an icon, you should double-click the left mouse button . (More)
Updated 4/7/2014 7:07:29 AM
Which system tool allows you to manage the available space on your hard disk to improve efficiency? A. Disk Defragmenter B. ScanDisk C. DriveSpace D. Anti-Virus
Weegy: B. DriveSpace User: Which of following options opens a program, folder, document, or a Web site? A. Start B. All Programs C. Control Panel D. Run (More)
Updated 4/7/2014 8:02:16 AM
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Updated 4/7/2014 7:12:35 AM
A screen saver is best described as a moving full-screen graphic.
Find the value of x in the equation 2(x – 3) + 5x = 5(2x + 6). A. 12 C. 2 B. –12 D. –2
Weegy: xUser: Find the possible values for s in the inequality 12s – 20 50 – 3s – 25. A. s 3 C. s 5/9 B. s 9 D. s 1/3 (More)
Updated 4/8/2014 6:54:09 AM
2(x – 3) + 5x = 5(2x + 6)
2x - 6 + 5x = 10x + 30
7x - 6 = 10x + 30
7x - 10x = 30 + 6
-3x = 36
x = -12
Confirmed by jeifunk [4/8/2014 7:06:32 AM]
Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23. A. r = 12, s = 0 C. r = 4, s = 3 B. r = –12, s = 9 D. r = –1, s = –3
Updated 4/8/2014 8:04:28 AM
3r – 4s = 0, multiply 2 on both sides: 6r - 8s = 0 (equation 1)
2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)
equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3
3r - 4(3) = 0, r = 12/3 = 4
The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3
Confirmed by jeifunk [4/8/2014 8:05:49 AM]
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