With the rush to California in the late 1840s this group of people dominated and discriminated against the other groups.
a.
Chinese
c.
Whites
b.
Blacks
d.
Indians

With the rush to California in the late 1840s, CHINESE people dominated and discriminated against the other groups.

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Asked 3/18/2016 6:35:23 AM

Updated 11/17/2018 6:28:44 PM

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Write the following equation in slope-intercept form. -x+5y=3

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Updated 3/12/2016 4:47:42 AM

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Under the Missouri Compromise, what state entered the union as a free state?

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Updated 3/11/2016 7:45:52 AM

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Who failed to become president despite winning most of the popular vote in 1824? **Weegy:** Andrew Jackson failed to become president despite winning most of the popular vote in 1824.
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Updated 12/23/2020 3:57:02 PM

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Write an equation for the line that passes through the points (6,-4) and (-2,-9)

Question|Asked by Finesse_King

Updated 322 days ago|5/26/2023 12:08:57 AM

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y - y1 = m(x - x1),

m = (y2 - y1) / (x2 - x1),

m = (-9 - (-4)) / (-2 - 6)

m = (-9 + 4) / (-2 - 6)

m = -5 / -8

m = 5/8

y - (-4) = (5/8)(x - 6)

y + 4 = (5/8)(x - 6)

Y + 4 = (5/8)x - 15/4

y = (5/8)x - 15/4 - 4

y = (5/8)x - 15/4 - 16/4

Simplifying the expression:

y = (5/8)x - 31/4

Therefore, the equation for the line passing through the points (6, -4) and (-2, -9) is y = (5/8)x - 31/4.

m = (y2 - y1) / (x2 - x1),

m = (-9 - (-4)) / (-2 - 6)

m = (-9 + 4) / (-2 - 6)

m = -5 / -8

m = 5/8

y - (-4) = (5/8)(x - 6)

y + 4 = (5/8)(x - 6)

Y + 4 = (5/8)x - 15/4

y = (5/8)x - 15/4 - 4

y = (5/8)x - 15/4 - 16/4

Simplifying the expression:

y = (5/8)x - 31/4

Therefore, the equation for the line passing through the points (6, -4) and (-2, -9) is y = (5/8)x - 31/4.

Added 322 days ago|5/26/2023 12:08:57 AM

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Write an equation for the line that goes through the point (3,-5) and is parallel to y=4x+6 **Weegy:** 2(4x + 2) = 8x + 4 (More)

Question|Asked by Finesse_King

Updated 322 days ago|5/26/2023 12:10:01 AM

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Using the point-slope form, we substitute the slope (m = 4) and the coordinates (x1 = 3, y1 = -5) into the equation:

y - y1 = m(x - x1)

y - (-5) = 4(x - 3)

y + 5 = 4(x - 3)

y + 5 = 4x - 12

y = 4x - 12 - 5

y = 4x - 17

Therefore, the equation for the line that is parallel to y = 4x + 6 and passes through the point (3, -5) is y = 4x - 17.

y - y1 = m(x - x1)

y - (-5) = 4(x - 3)

y + 5 = 4(x - 3)

y + 5 = 4x - 12

y = 4x - 12 - 5

y = 4x - 17

Therefore, the equation for the line that is parallel to y = 4x + 6 and passes through the point (3, -5) is y = 4x - 17.

Added 322 days ago|5/26/2023 12:09:55 AM

This answer has been confirmed as correct and helpful.

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