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Input the equation of the given line in standard form.The line with m = -3/4 and b = -2.
Question
Asked 10/23/2013 1:55:33 PM
Updated 7/27/2014 12:30:59 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/27/2014 12:30:24 AM]
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User: Input the equation of the given line in standard form.The line with m = -3/4 and b = -2.

Weegy: First, create a slope-intercept equation. y= (-1/2)x + b To find b, plug in (-2, -3) -3 = (-1/2)(-2) + b -3 = 1 + b -4 = b y= (-1/2)x - 4 Now convert to standard form, which means getting both x and y on the same side. [ So we can add (1/2)x to each side (1/2)x + y = -4 multiply by two to get rid of the fraction x + 2y = -8 ]
blakstermc|Points 58|

Question
Asked 10/23/2013 1:55:33 PM
Updated 7/27/2014 12:30:59 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/27/2014 12:30:24 AM]
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The equation of the line with m = -3/4 and b = -2 in standard form is 3x + 4y = -8
Added 7/27/2014 12:30:59 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/27/2014 1:41:18 PM]
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Questions asked by the same visitor
The line through (0, -3) and (3, 0)
Weegy: 7/5 User: Input in standard form the equation of the given line. The line through (0, -3) and (3, 0) User: 3x - 2y = 6 m = y-intercept Weegy: The y-intercept of the line whose equation is 3x - 2y = 6 is A.-3 User: 3x - 2y = 6 m = Weegy: Input: lcm(5/3 x^2 y-4/6 x y^3) Result: lcm((5 x^2 y)/3-(2 x y^3)/3) ListPointPlot3D[Table[{x, y, LCM[(x y (5 x - 2 y^2))/3]}, {x, -10, 10}, {y, -10, 10}], [ PlotRange -> All] Alternate Form: lcm(1/3 x y (5 x-2 y^2)) ] (More)
Question
Not Answered
Updated 4/28/2014 9:40:23 PM
2 Answers/Comments
The line through (0, -3) and (3, 0) in standard form is x - y = 3

Added 4/28/2014 9:37:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/28/2014 9:39:36 PM]
3x - 2y = 6
-2y = -3x + 6
y = 3/2x - 3 which is the slope intercept form
so slope m = 3/2, y intercept = -3
Added 4/28/2014 9:40:23 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/28/2014 9:41:16 PM], Unconfirmed by jeifunk [4/28/2014 9:41:17 PM], Confirmed by jeifunk [4/28/2014 9:41:18 PM]
Solve the given equation for the slope and y-intercept. 2x + 5y + 1 = 0
Question
Not Answered
Updated 7/26/2014 9:21:50 AM
1 Answer/Comment
2x + 5y + 1 = 0
5y = -2x - 1
y = -2/5x - 1/5 which is the slope intercept form of the line equation.
Added 7/26/2014 9:21:50 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/26/2014 9:34:17 AM]
Find the common solution. 7x + 2y = 4 y = x + 1
Weegy: 2x +7y = 5 Just move the second one to the first one and then the answer is that in above. (More)
Question
Not Answered
Updated 5/24/2014 9:45:40 AM
1 Answer/Comment
7x + 2y = 4
y = x + 1
using the second equation to institute y in the first one:
7x + 2(x + 1) = 4
7x + 2x + 2 = 4
9x = 4 - 2
x = 2/9
y = 2/9 + 1 = 2/9 + 9/9 = 11/9
The solution for the system 7x + 2y = 4 y = x + 1 is (2/9, 11/9)
Added 5/24/2014 9:45:40 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/24/2014 11:57:24 AM]
Find the slope of the (3, 8) and (-2, 5)
Weegy: 1/25 User: Find the slope of (2, 1) and (-1, -1) (More)
Question
Updated 7/29/2018 8:02:33 AM
1 Answer/Comment
The slope of the (3, 8) and (-2, 5) is ; m = y1-y0 /x1-x0 = 5 - 8 / -2 -3 = -3 /-5 = 3/5 = 0.6
Added 7/29/2018 8:02:27 AM
This answer has been confirmed as correct and helpful.
Find the slope of 2, 1 and -1, -1
Question
Updated 7/5/2014 11:58:51 AM
1 Answer/Comment
The slope of the line passing through points (2, 1) and (-1, -1) is: 2/3.

m = (y2 - y1)/(x2 - x1)

m = (-1 - 1)/(-1 - 2)

m = -2/-3

m = 2/3
Added 7/5/2014 11:58:51 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/5/2014 12:25:10 PM]
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