50 J of work was performed in 20 seconds. How much power was used to do this task? A. 24.5 W B. 0.4 W C. 2.5 W D. 4 W
50 J of work was performed in 20 seconds. 2.5 W of power was used to do this task. Solution: Power = (amount of work done) / (time to do the work); = (50 J) / (20 sec); = 2.5 joule/sec = 2.5 watts.
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