Capacity: C=Blog 2 (1+SNR), B=3000Hz, SNR=9

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Channel Capacity Formula: C = B log&sub2;(1 + SNR) Step 1: Identify values B = 3000 Hz SNR = 9 Step 2: Apply formula C = 3000 × log&sub2;(1 + 9) C = 3000 × log&sub2;(10) Step 3: Convert log base 2 log&sub2;(10) = log(10) ÷ log(2) = 2.3026 ÷ 0.6931 ≈ 3.322 Step 4: Multiply C = 3000 × 3.322 C ≈ 9966 bits/s

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Asked 14 days ago|4/29/2026 9:56:41 AM

Updated 14 days ago|4/29/2026 10:52:11 AM

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alfred123

Channel Capacity Formula:
C = B log&sub2;(1 + SNR)

Step 1: Identify values
B = 3000 Hz
SNR = 9

Step 2: Apply formula
C = 3000 × log&sub2;(1 + 9)
C = 3000 × log&sub2;(10)

Step 3: Convert log base 2
log&sub2;(10) = log(10) ÷ log(2)
= 2.3026 ÷ 0.6931
≈ 3.322

Step 4: Multiply
C = 3000 × 3.322
C ≈ 9966 bits/s

Added 14 days ago|4/29/2026 10:51:16 AM

This answer has been confirmed as correct and helpful.

alfred123

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Added 14 days ago|4/29/2026 10:52:11 AM

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Deleted by alfred123 [4/29/2026 10:52:20 AM]

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