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An Antique dealer visited three shops. she spend $25 at the first shop. At the second shop, she spent half of her remaining money. At the third shop, she spent one third of her remaining money and had $60 left. How much money did the dealer have orginally?
the dealer had $205.
Expert answered|manaweegy|Points 90|
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Asked 9/21/2011 9:00:13 PM
Updated 349 days ago|7/31/2025 1:22:35 PM
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Let the original amount be x.
After first shop:
Remaining money = x - 25
At second shop:
Spent half of remaining, so remaining = (1/2)(x - 25)

At third shop:
Spent one third of remaining, so remaining = (2/3) × (1/2)(x - 25) = (1/3)(x - 25)
After third shop, money left = $60:
(1/3)(x - 25) = 60
Multiply both sides by 3:
x - 25 = 180
Add 25 to both sides:
x = 205
Answer: The dealer originally had $205.
Added 349 days ago|7/31/2025 1:22:35 PM
This answer has been confirmed as correct and helpful.
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