Which of the following is the greatest common factor of the terms 48s5t3u2 and 40s3tu4?
A. 6s2t2u C. 6s3tu
B. 8s2t2u D. 8s3tu2

The greatest common factor of the terms 48s^5t^3u^2 and 40s^3tu^4 is: D. 8s^3tu^2

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The greatest common factor of the terms 48s^5t^3u^2 and 40s^3tu^4 is: D. 8s^3tu^2

Added 4/8/2014 7:58:32 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/8/2014 8:06:03 AM]

To start a program from an icon, you should
A. click the right mouse button.
B. click both mouse buttons at once.
C. double-click the left mouse button.
D. click the left mouse button. **Weegy:** To start a program from an icon, you should double-click the left mouse button .
(More)

Question|Asked by masterquece

Expert Answered

Updated 4/7/2014 7:07:29 AM

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Which system tool allows you to manage the available space on your hard disk to improve efficiency?
A. Disk Defragmenter
B. ScanDisk
C. DriveSpace
D. Anti-Virus **Weegy:** B. DriveSpace **User:** Which of following options opens a program, folder, document, or a Web site?
A. Start
B. All Programs
C. Control Panel
D. Run (More)

Question|Asked by masterquece

Not Answered

Updated 4/7/2014 8:02:16 AM

1 Answer/Comment

Disk Defragmenter allows you to manage the available space on your hard disk to improve efficiency.

Added 4/7/2014 8:02:16 AM

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A screen saver is best described as a(n)
A. desktop background pattern or wallpaper.
B. antistatic monitor dust cover.
C. moving full-screen graphic.
D. stationary display, such as a menu or desktop

Question|Asked by masterquece

Not Answered

Updated 4/7/2014 7:12:35 AM

1 Answer/Comment

A screen saver is best described as a moving full-screen graphic.

Added 4/7/2014 7:12:35 AM

This answer has been confirmed as correct and helpful.

Find the value of x in the equation 2(x – 3) + 5x = 5(2x + 6).
A. 12 C. 2
B. –12 D. –2 **Weegy:** x**User:** Find the possible values for s in the inequality 12s – 20 50 – 3s – 25.
A. s 3 C. s 5/9
B. s 9 D. s 1/3 (More)

Question|Asked by masterquece

Not Answered

Updated 4/8/2014 6:54:09 AM

1 Answer/Comment

Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23.
A. r = 12, s = 0 C. r = 4, s = 3
B. r = –12, s = 9 D. r = –1, s = –3

Question|Asked by masterquece

Updated 4/8/2014 8:04:28 AM

1 Answer/Comment

3r – 4s = 0, multiply 2 on both sides: 6r - 8s = 0 (equation 1)

2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)

equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3

3r - 4(3) = 0, r = 12/3 = 4

The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3

2r + 5s = 23, multiply 3 on both sides: 6r + 15s = 69 (equation 2)

equation 2 - equation 1 we get: 23s = 69, s= 69/23 = 3

3r - 4(3) = 0, r = 12/3 = 4

The solution for the system of equations 3r – 4s = 0 and 2r + 5s = 23 is C. r = 4, s = 3

Added 4/8/2014 8:04:28 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [4/8/2014 8:05:49 AM]

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