35k 2 + 29k + 6
35k^2 + 29k + 6 = (5k + 2)(7k + 3)
Question
Updated 12/22/2014 11:23:56 AM
s
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35k^2 + 29k + 6 = (5k + 2)(7k + 3)
Confirmed by sujaysen [12/22/2014 11:25:45 AM]

Questions asked by the same visitor
Find the product. 3y 2 z(2y 2 z + 4yz - y + z)
Weegy: Find the product. 3y 2 z(2y 2 z + 4yz - y + z) is 6 y z (8 y z-y+z) . User: Find the quotient. (35n 3 - 30n 2 + 25n) ÷ (-5n) User: Find the product. (2p + 7)(3p - 9) Weegy: 3-3 = 0 User: Simplify 5 + 2{x - 4[3x + 7(2 - x)]}. Weegy: The solution set for x + y = 5, x - 2y = 2 is {x = 4, y = 1}. (x + y = 5) * 2: 2x + 2y = 10; (2x + 2y = 10) + (x - 2y = 2): 3x = 12; x = 12/3; x = 4; 4 + y = 5; y = 5 - 4; y = 1 User: Find the product. (7q - 5)(7q + 5) Weegy: 49q^2-25 is the product. User: Find the product. -mnp(3m - 5n + 7p) User: Find the product. (6a + b)2 Weegy: (6a+b)^2 = (6a+b) (6a+b) = 36a^2 + 6ab + 6ab + b^2 = 36a^2 + 12ab + b^2 User: Find the product. (-d + 4)(-d - 4) Weegy: (-d + 4)(-d - 4); d^2 + 4d - 4d - 16 = d^2 - 16 User: Find the quotient. 48a 3 bc 2 ÷ 3abc User: Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X · Y - Z] ÷ X. Weegy: Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X ? Y - Z] ? X. (r+2*2r-9-r2+17r+30)/r+2 = r+4r-9-r2+17r+30/r+2 = 5r-9-r2+17r+30/r+2 = -r2+5r-9+17r+30/r+2 = -r2+22r-9+30/r+2 = -r2+22r+21/r+2 User: Simplify b(a + b) - a(a - b). Weegy: b(a + b) - a(a - b) (ab + b^2) - (a^2 + ab) = -a^2 +2ab + b^2 User: Multiply (6z 2 - 4z + 1)(8 - 3z). Weegy: (6z^2 - 4z + 1)(8 - 3z) is equals to -18z^3 + 60z^2 - 35z + 8 User: Find the quotient. y 9 ÷ y 3 User: Perform the long division and check in your notebook. Select the correct answer. (y 3 - 125) ÷ (y - 5) Weegy: 3-3 = 0 User: (y 3 - 125) ÷ (y - 5) Weegy: 3-3 = 0 User: Find the product. -2x(x 2 - 3) User: Select the GCF of these numbers. 25 · 5· 11 and 23· 52 · 7 Weegy: The answer is 1. The Greatest Common Factor (GCF) of the numbers 25 ? 5? 11 and 23? 52 ? 7 is 1 because 1 is the greatest number that divides evenly into all of them. User: 25 · 5· 11 and 23· 52 · 7 Weegy: 23^52 is about 6.454 * 10^70 or 64 duovigintillion. User: Find the GCF of the ... (More)
Question
Updated 12/22/2014 7:38:45 PM
(2p + 7)(3p - 9) = 6p^2 - 18p + 21p - 63 = 6p^2 + 3p - 63
Confirmed by yumdrea [12/22/2014 7:36:35 PM]
5 + 2{x - 4[3x + 7(2 - x)]}
= 5 + 2[x - 4(3x + 14 - 7x)]
= 5 + 2[x - 4(14 - 4x)]
= 5 + 2(x - 56 +16x)
= 5 + 2(17x - 56)
= 5 + 34x - 112
= 34x - 107
Confirmed by yumdrea [12/22/2014 7:38:59 PM]
(y^3 - 125) ÷ (y - 5) = y^2 + 5y + 25
Confirmed by yumdrea [12/22/2014 7:52:44 PM]
-2x(x^2 - 3) = -2x^3 + 6x
Confirmed by yumdrea [12/22/2014 7:55:26 PM]
The GCF of numbers 2^5 · 5· 11 and 2^3 · 5^2 · 7 is 2^3 · 5
Confirmed by yumdrea [12/22/2014 7:55:24 PM]
31,130,169
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