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factor the polynomial y^2-5y
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Question
Asked 11/21/2011 9:44:20 PM
Updated 6/9/2014 1:20:39 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by
jerry06
[6/9/2014 1:20:39 PM]
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factor the polynomial y^2-5y
Original conversation
User:
factor the polynomial y^2-5y
Weegy:
Reduce the expression -(5y)/(y^(2)) by removing a factor of y from the numerator and denominator. (y^(2)-(5)/(y)+7y+12)/(y^(3)-14y^(2)+(45y)/(y^(2))+9y+18) To add fractions, the denominators must be equal. [ The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is y. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. ]
Expert answered|
MissWitty
|Points 197|
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Question
Asked 11/21/2011 9:44:20 PM
Updated 6/9/2014 1:20:39 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by
jerry06
[6/9/2014 1:20:39 PM]
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8
jerry06
y^2 - 5y = y(y - 5)
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Added 6/9/2014 1:20:38 PM
This answer has been confirmed as correct and helpful.
Confirmed by
andrewpallarca
[6/9/2014 1:24:22 PM]
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2x dx = x².
Weegy: (2x + 1)? = (2x + 1)(2x + 1) = 4x? + 4x + 1 Answer: 4x? + 4x + 1
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limit (x²-1)/(x-1) = x+1.
Weegy: 5/7(x+y)-1/7(x-1)= 5x + 5y/7 - x - 1/7 = 5x - x + 5y - 1/7 = 4x + 5y - 1/7
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