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From position B, the angle of elevation to T at the top of the tower is 64. From position A, the angle of elevation to T at the top of the tower is 69. The distance AB is 4.8 metres and the height of the student to eye level is 1.5 metres. Find the height of the tower.
Question
Asked 10/27/2008 10:50:45 AM
Updated 303 days ago|8/13/2025 8:36:54 AM
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User: From position B, the angle of elevation to T at the top of the tower is 64. From position A, the angle of elevation to T at the top of the tower is 69. The distance AB is 4.8 metres and the height of the student to eye level is 1.5 metres. Find the height of the tower.

Weegy: [www.sosmath.com/]

Question
Asked 10/27/2008 10:50:45 AM
Updated 303 days ago|8/13/2025 8:36:54 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
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Define variables
Let:
- Distance from B to the base of the tower: x
- Distance from A to the base: x + 4.8
- Height of the tower above student's eye level: h
(so total tower height H = h + hs)
Use tangent for angle of elevation
From B: tan( B) = h / x => h = x * tan(64°)
From A: tan( A) = h / (x + 4.8) => h = (x + 4.8) * tan(69°)
Equate the two expressions for h
x * tan(64°) = (x + 4.8) * tan(69°)
x * (tan(64°) - tan(69°)) = 4.8 * tan(69°)
x = (4.8 * tan(69°)) / (tan(64°) - tan(69°))
Calculate values
tan(64°) = 2.0503, tan(69°) = 2.6051
x = (4.8 * 2.6051) / (2.0503 - 2.6051)
x 12.5045 / (-0.5548)
x = -22.54 m (ignore negative, distance = 22.54 m)
Find height above eye level
h = x * tan(64°) = 22.54 * 2.0503 = 46.2 m
Add student's eye level
H = h + hs = 46.2 + 1.5 = 47.7 m
Answer:
H = 47.7 m
Added 303 days ago|8/13/2025 8:36:48 AM
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