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identify and describe each conic section (x+2)^2 + (y-8)^2=64
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Asked 5/21/2013 8:30:05 PM
Updated 5/4/2015 2:25:31 AM
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Flagged by janezeshun [5/4/2015 2:22:47 AM]
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User: identify and describe each conic section (x+2)^2 + (y-8)^2=64



Weegy: (x+2)^2 + (y-8)^2=64 (x+2)^2+y^2 = 16 y x^2+4 x+y^2-16 y = -4 x^2+4 x+y^2-16 y+4 = 0 x = -10, y = 8 x = -2, y = 0 x = -2, y = 16 x = 6, [ y = 8 y = 8-sqrt(-x^2-4 x+60) y = sqrt(-x^2-4 x+60)+8 (dx(y))/(dy) = (8-y)/(2+x) (dy(x))/(dx) = (2+x)/(8-y) ]
Expert answered|trixxysexy|Points 0|

Question
Asked 5/21/2013 8:30:05 PM
Updated 5/4/2015 2:25:31 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by janezeshun [5/4/2015 2:22:47 AM]
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(x+2)^2 + (y-8)^2=64 is a circle with center is (-2 , 8) and radius is 8 .
Added 5/4/2015 2:25:31 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/4/2015 3:25:19 AM]
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