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Based on the lesson, which of the following would be the best approach for solving this system by substitution? 5x = y + 6 2x - 3y = 4 Solve the first equation for x. Solve the first equation for y. Solve the second equation for x. Solve the second equation for y.
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Asked 5/15/2014 9:15:45 PM
Updated 5/17/2014 2:44:23 AM
1 Answer/Comment
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Flagged by yeswey [5/17/2014 2:42:07 AM]
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User: Based on the lesson, which of the following would be the best approach for solving this system by substitution? 5x = y + 6 2x - 3y = 4 Solve the first equation for x. Solve the first equation for y. Solve the second equation for x. Solve the second equation for y.

Weegy: 4(5x - 6) - 4(2x + 1) is equal to 12x-28. SOLUTION: 4(5x - 6) - 4(2x + 1); 20x-24-8x-4; 20x-8x-24-4; 12x-28
lakki|Points 61|

Question
Asked 5/15/2014 9:15:45 PM
Updated 5/17/2014 2:44:23 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [5/17/2014 2:42:07 AM]
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The best approach for solving this system 5x = y + 6, 2x - 3y = 4 by substitution is: Solve the first equation for y.
Added 5/17/2014 2:44:23 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/17/2014 12:36:46 PM]
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Questions asked by the same visitor
The system shown has _____ solution(s). y = x + 1 2y - x = 2 no one infinite
Weegy: y=x+12_y-x=2... Replace all occurrences of y with the solution found by solving the last equation for y. [ In this case, the value substituted is x+12. y=x+12_(x+12)-x=2.. Remove the parentheses around the expression x+12. y=x+12_x+12-x=2... Since x and -x are like terms, add -x to x to get 0. y=x+12_0+12=2... Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression. y=x+12_12=2... Since 12 is not equal to 2, there are no solutions. The system shown has no Solutions. ] User: Which of the following equations is equivalent to x - y = 5? x - 2y = 30 4x - 3y = 30 3x - 4y = 30 Weegy: 3x - 4y = 30 (More)
Question
Updated 5/15/2014 11:20:35 PM
1 Answer/Comment
y = x + 1
2y - x = 2
institue y in the second equation the result is:
2(x + 1) - x = 2
2x + 2 - x = 2
x = 2 - 2 = 0
y = 0 + 1 = 1
The solution for the system y = x + 1, 2y - x = 2 is (0, 1)
Added 5/15/2014 11:20:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/15/2014 11:23:50 PM]
x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at which point? (1, -1) (-1, 1) (0, 3/2)
Question
Updated 5/15/2014 11:23:42 PM
1 Answer/Comment
x - 2y = 3; 5x + 3y = 2 The lines whose equations are shown intersect at (1, -1).
x - 2y = 3 rearrange the equation we get:
x = 2y + 3 (first equation)
5x + 3y = 2 (second equation)
institute x in the second equation the result is:
5(2y + 3) + 3y = 2
10y + 15 + 3y = 2
13y = -13
y = -1,
x = 2y + 3 = -2 + 3 = 1
The solution for the system is (1, -1)
Added 5/15/2014 11:23:42 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/16/2014 12:27:40 AM]
For the following system, use the second equation to make a substitution for x in the first equation. x + 5y - 10 = 0 x = 2y - 8 What is the resulting equation in simplest form? -3y - 18 = 0 3y - 18 = 0 7y - 18 = 0
Weegy: 3y - 18 = 0 (More)
Question
Updated 5/15/2014 11:16:37 PM
1 Answer/Comment
For the following system, x + 5y - 10 = 0; x = 2y - 8, use the second equation to make a substitution for x in the first equation. The resulting equation in simplest form is: 7y - 18 = 0.
x + 5y - 10 = 0;
x = 2y - 8,
institute x in the first equation:
2y - 8 + 5y - 10 = 0
7y - 18 = 0
Added 5/15/2014 11:16:37 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/15/2014 11:24:06 PM]
Solve the following system of equations by the substitution method. x - y = 0 x - y - 2 = 0 What is the solution set? {(1, -1)} {(-1, 1)} Ø
Weegy: The answer is A.(3, -1) Solution: let x = 3 and y = -1 x - y = 4 3 - (-1) = 4 4 = 4 x + y = 2 3 + -1 = 2 2 = 2 For the graph follow this link (More)
Question
Updated 5/17/2014 10:05:16 AM
1 Answer/Comment
x - y = 0 rearranging the equation we get"
x = y (the first equation)
x - y - 2 = 0 (the second equation)
institute x in the second equation using the first one the result is:
y - y - 2 = 0
-2 = 0 which is a false statement.
Therefore, there is no solution for the system x - y = 0 x - y - 2 = 0.
Added 5/17/2014 10:05:16 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/17/2014 12:36:35 PM]
Solve |2x - 5| = 4. {x | x = -4.5 or x = 4.5} {x | x = 0.5 or x = 4.5} {x | 0.5
Weegy: 3(x - 2) = -4(5 + x); 3x - 6 = -20 - 4x; 3x + 4x = -20 + 6; 7x = -14; x = -14/7; x = -2 (More)
Question
Updated 5/19/2014 11:38:31 PM
1 Answer/Comment
|2x - 5| = 4
2x - 5 = 4 or 2x - 5 = - 4
2x = 9 or 2x = 1
x = 4.5 or x = 0.5
Added 5/19/2014 11:38:31 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/20/2014 10:13:23 AM]
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