How many atomic bombs were dropped on Japan during World War II? none one two three
Question
Asked 6/11/2013 9:14:02 AM
Updated 2/16/2015 1:14:39 PM
Flagged by alfred123 [2/16/2015 1:14:39 PM]
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Original conversation
User: How many atomic bombs were dropped on Japan during World War II? none one two three

Question
Asked 6/11/2013 9:14:02 AM
Updated 2/16/2015 1:14:39 PM
Flagged by alfred123 [2/16/2015 1:14:39 PM]
Rating
3
TWO atomic bombs were dropped on Japan during World War II.
Added 2/16/2015 1:14:37 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [2/16/2015 1:16:30 PM]

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Questions asked by the same visitor
The equation of the circle whose center is at (3, 7) and whose radius is 6 is (x + 3)² + (y + 7)² = 6 (x + 3)² + (y + 7)² = 36 (x - 3)² + (y - 7)² = 36
Weegy: the radius is 6 User: |P1P2| = d = (More)
Question
Updated 7/3/2014 8:41:51 PM
The equation of the circle whose center is at (3, 7) and whose radius is 6 is: (x - 3)² + (y - 7)² = 36
Added 7/3/2014 8:41:51 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:01:51 PM]
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Updated 7/3/2014 8:40:00 PM
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
4y2 + 25y + 6
Weegy: 4y2 + 25y + 6 = (y + 6) (4y + 1) User: Factor 6a^2 - 23a - 4. (More)
Question
Updated 8/3/2014 9:54:34 PM
6a^2 - 23a - 4 = (a - 4) (6a + 1)
Added 8/3/2014 9:51:06 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/3/2014 9:54:12 PM]
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