Question and answer
How many atomic bombs were dropped on Japan during World War II? none one two three
Question
Asked 6/11/2013 9:14:02 AM
Updated 2/16/2015 1:14:39 PM
1 Answer/Comment
Flagged by alfred123 [2/16/2015 1:14:39 PM]
s
Get an answer
Original conversation
User: How many atomic bombs were dropped on Japan during World War II? none one two three

Question
Asked 6/11/2013 9:14:02 AM
Updated 2/16/2015 1:14:39 PM
1 Answer/Comment
Flagged by alfred123 [2/16/2015 1:14:39 PM]
New answers
Rating
3
TWO atomic bombs were dropped on Japan during World War II.
Added 2/16/2015 1:14:37 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [2/16/2015 1:16:30 PM]
Comments

There are no comments.

Add an answer or comment
Log in or sign up first.
Questions asked by the same visitor
The equation of the circle whose center is at (3, 7) and whose radius is 6 is (x + 3)² + (y + 7)² = 6 (x + 3)² + (y + 7)² = 36 (x - 3)² + (y - 7)² = 36
Weegy: the radius is 6 User: |P1P2| = d = (More)
Question
Not Answered
Updated 7/3/2014 8:41:51 PM
1 Answer/Comment
The equation of the circle whose center is at (3, 7) and whose radius is 6 is: (x - 3)² + (y - 7)² = 36
Added 7/3/2014 8:41:51 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:01:51 PM]
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
1 Answer/Comment
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Added 1/28/2018 7:24:33 AM
This answer has been confirmed as correct and helpful.
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
1 Answer/Comment
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Added 7/3/2014 8:40:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Not Answered
Updated 7/3/2014 8:40:00 PM
2 Answers/Comments
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Added 7/3/2014 8:40:00 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
4y2 + 25y + 6
Weegy: 4y2 + 25y + 6 = (y + 6) (4y + 1) User: Factor 6a^2 - 23a - 4. (More)
Question
Not Answered
Updated 8/3/2014 9:54:34 PM
1 Answer/Comment
6a^2 - 23a - 4 = (a - 4) (6a + 1)
Added 8/3/2014 9:51:06 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/3/2014 9:54:12 PM]
31,999,348
questions answered
GET
Answers.
GET THE APP.
weegy*
*
Get answers from Weegy and a team of really smart live experts.
Popular Conversations
S
L
Points 804 [Total 3801] Ratings 2 Comments 784 Invitations 0 Offline
S
L
P
L
P
Points 776 [Total 6799] Ratings 1 Comments 766 Invitations 0 Offline
S
L
P
R
P
R
L
P
P
C
R
P
R
L
P
R
Points 697 [Total 12788] Ratings 1 Comments 467 Invitations 22 Online
S
L
P
1
Points 540 [Total 3396] Ratings 3 Comments 510 Invitations 0 Offline
S
L
Points 406 [Total 1899] Ratings 1 Comments 396 Invitations 0 Offline
S
L
Points 302 [Total 4686] Ratings 1 Comments 292 Invitations 0 Offline
S
L
1
Points 170 [Total 3481] Ratings 2 Comments 150 Invitations 0 Offline
S
L
Points 125 [Total 276] Ratings 3 Comments 95 Invitations 0 Offline
S
L
Points 85 [Total 244] Ratings 0 Comments 85 Invitations 0 Offline
S
L
L
Points 64 [Total 5352] Ratings 1 Comments 54 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)
Home | Contact | Blog | About | Terms | Privacy | © Purple Inc.