Question and answer
Factor -3bk 2 + 9bk - 6b. -3b(k + 1)(k - 2) -3b(k - 1)(k + 2) -3b(k - 1)(k - 2)
Question
Asked 11/14/2014 10:33:37 AM
Updated 11/14/2014 12:46:38 PM
2 Answers/Comments
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Original conversation
User: Factor -3bk 2 + 9bk - 6b. -3b(k + 1)(k - 2) -3b(k - 1)(k + 2) -3b(k - 1)(k - 2)

Weegy: -3bk^2 + 9bk - 6b = -3b(k - 1)(k - 2)




User: Factor 2x 2 - 10x - 12. 2(x + 2)(x - 3) 2(x - 1)(x + 6) 2(x - 6)(x + 1)

Weegy: 2x2 10x 12
=2(x2 5x 6)
=2(x+1)(x 6)



User: Choose the product. a 2 b 3 · 6ab 2 6a 2b 5 6a 2b 6 6a 3b 5

User: Find the sum and choose the correct answer. 2n 3 + 4n 2 - 7 and -n 3 - 8n - 2 -n3 + 4n2 - 8n - 9 n3 + 4n2 - 8n - 9 n3 + 4n2 - 8n - 5 n3 - 4n2 -9

Weegy: Can you provide us the options and clarify the equation given please.
jeifunk|Points 36842|

User: Select the correct difference. -3z 5 - (-7z 5) -10z5 -4z5 4z5 4z

User: Factor k 2 + 8k + 15. (k + 1)(k + 15) (k + 8)(k + 7) (k + 3)(k + 5)

Weegy: k^2 + 8k + 15
The factored form is (k + 3)(k + 5)



User: Factor the four-term polynomial. ab + ac - 4b - 4c (a - 4)(b + c) (a - c)(b + 4) (a + 4)(b - c)

Question
Asked 11/14/2014 10:33:37 AM
Updated 11/14/2014 12:46:38 PM
2 Answers/Comments
New answers
Rating
5
ab + ac - 4b - 4c;
a(b + c) - 4(b + c);
(a - 4)(b + c);
Added 11/14/2014 12:44:40 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [11/14/2014 12:50:21 PM]
5
The sum of 2n^3 + 4n^2 - 7 and -n^3 - 8n - 2 can be calculated as follows:


(2n^3 + 4n^2 - 7) + (-n^3 - 8n - 2);
n^3 + 4n^2 - 8n - 9;
Added 11/14/2014 12:46:38 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/14/2014 12:51:47 PM]
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Questions asked by the same visitor
Find the greatest common factor of 15x 2 y 3 and -20x 3 yz.
Question
Not Answered
Updated 11/17/2014 9:09:13 PM
1 Answer/Comment
The greatest common factor of 15x^2y^3 and -20x^3yz is 5x^2y.
15x^2y^3 = 3*5x^2y^3
-20x^3yz = -4*5x^3yz
Added 11/17/2014 9:09:13 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/18/2014 12:52:12 AM]
Divide 8y 7 ÷ 4y 5
Weegy: The result of (4y)^3/8y is 8y^2 User: find the right quotient. 36m 5 n 5 ÷ (12m 3) Weegy: 36m^5 n^5 ? (12m^3) = 3m^2 n^5 User: Find the quotient. 12 a3 p4 ÷ -2a2p -6a3p5 -24ap3 -6ap3 6a5p3 User: Find the quotient. 4z a + 2 ÷ (-8z a - 2) -z-4 -z -z2a -z4 (More)
Question
Not Answered
Updated 11/24/2014 12:29:05 AM
1 Answer/Comment
8y^7 ÷ 4y^5
= (8/4)*(y^7/y^5)
= 2*y^2
= 2y^2

Added 11/24/2014 12:28:42 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/24/2014 12:54:47 AM]
Factor this expression completely : mr+ ns - nr - ms
Question
Updated 11/18/2014 10:13:57 PM
1 Answer/Comment
mr + ns - nr - ms
= mr - ms + n(s - r)
= m(r - s) + n(s - r)
= (r - s)( m - n)
Added 11/18/2014 10:07:14 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/18/2014 10:31:49 PM]
Find the quotient. (4ab - 8a 2 + 12ac) ÷ 4a b - 2a2 + 3c b - 2a + 3c abc
Weegy: (4ab - 8a 2 + 12ac) ? 4a b - 2a2+ 3c b - 2a + 3c abc. If i find the quotient of this equation. The answer is 5a+10b=25c User: Find the quotient. 48j 5 k 2÷ (-3j 3 k) -16j2k -16j3k2 -16j3k (More)
Question
Not Answered
Updated 11/15/2014 2:42:39 AM
2 Answers/Comments
(4ab - 8a^2 + 12ac) ÷ 4a
= 4ab/4a - 8a^2/4a + 12ac/4a
= b - 2a +3c
Added 11/15/2014 2:41:37 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/15/2014 2:53:45 AM], Rated good by jeifunk
48j^5k^2 ÷ (-3j^3k)
= -16j^2k
Added 11/15/2014 2:42:32 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [11/15/2014 2:54:00 AM], Rated good by jeifunk
Factor 2x 2 - 10x + 8 completely. 2(x + 2)(x - 2) 2(x - 1)(x - 4) 2(x - 2)(x + 4) User: Factor 4b 2 - 9. (4b + 3)(b - 3) (2b + 3)(2b - 3) (2b - 4)(2b - 5) User: How many terms are in the polynomial abcd + e - h 2? two three five six
Question
Not Answered
Updated 11/16/2014 9:48:53 PM
1 Answer/Comment
There are 3 terms in the polynomial abcd + e - h^2.
Added 11/16/2014 9:48:53 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [11/16/2014 10:11:27 PM]
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