Which of the following points is in the solution set of y < x2 - x

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Which of the following points is in the solution set of y < x2 - x - 6? (-2, -1)? (0, -5)? (3, 0)?

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Asked 3/23/2015 7:25:12 AM

Updated 4/26/2015 1:19:54 AM

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Flagged by yeswey [4/26/2015 1:19:18 AM]

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User: Which of the following points is in the solution set of y < x2 - x - 6? (-2, -1)? (0, -5)? (3, 0)?

Weegy: 2(x - 4) = 6(x + 2)

2x - 8 = 6x + 12;

2x - 6x = 12 + 8;

-4x = 20;

x = -20/4;

x = -5

User: Which of the following equations is of a parabola with a vertex at (1, 2)? y = (x - 1)^2 - 2 y = (x - 1)^2 + 2 y = (x + 1)^2 - 2 y = (x + 1)^2 + 2

User: What is the solution set of 6x^2 - 24 = 0? {-2, 2} {-2} {2}

User: A circle has a diameter with endpoints of (-2, 8) and (6, 4). What is the center of the circle? (8, 12) (4, 12) (2, 6)

User: Graph y > (x + 2)2

User: Write the quadratic equation in general form. What is the value of b^2 - 4ac? 1 = 2x^2 + 7x 40 41 57

User: Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9). (2, -7) (1, -4) (1, -2)

Weegy: (1, -2) is the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).
Andrew.|Points 50304|

User: y(y + 4) - y = 6 is a quadratic equation. True False

User: If (x + 1)(x - 3) = 5, then which of the following statements is true? x + 1 = 0 or x - 3 = 0 x + 1 = 5 or x - 3 = 5 x - 4 = 0 or x + 2 = 0

Weegy: x^2 - x - 12 = 0;

(x - 4) (x + 3) = 0;

x - 4 = 0; x = 4;
x + 3 = 0; x - 3;

x = {4, -3}

User: Which of the following statements follows from (x - 3)2 = 5? x2 + 9 = 5 x - 3 = ± square root of 5 x - 3 = ±25

User: Which of the following describes the translation of the graph of y = x^2 to obtain the graph of y = -x^2 - 3? reflect over the x-axis and shift left 3 reflect over the x-axis and shift down 3 reflect over the y-axis and shift down 3

Question

Asked 3/23/2015 7:25:12 AM

Updated 4/26/2015 1:19:54 AM

4 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by yeswey [4/26/2015 1:19:18 AM]

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yeswey

(-2, -1) is in the solution set of y < x^2 - x - 6.
when x = -2,
(-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0 > -1

Added 4/26/2015 1:16:00 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [4/26/2015 2:31:28 AM]

yeswey

y(y + 4) - y = 6 is a quadratic equation. True.
y(y + 4) - y = 6
y^2 + 4y - y = 6
y^2 + 3y - 6 = 0
It is a quadratic equation.

Added 4/26/2015 1:17:39 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [4/26/2015 2:32:08 AM]

yeswey

(x + 1)(x - 3) = 5
x^2 - 2x - 3 = 5
x^2 - 2x - 8 = 0
(x - 4)(x + 2) = 0
x - 4 = 0 or x + 2 = 0
if (x + 1)(x - 3) = 5 the true statement is x - 4 = 0 or x + 2 = 0

Added 4/26/2015 1:19:15 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [4/26/2015 2:32:27 AM]

yeswey

x - 3 = ± square root of 5 follows from (x - 3)^2 = 5.

Added 4/26/2015 1:19:54 AM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [4/26/2015 2:32:56 AM]

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Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 8x2 - 6x + 1 = 0 User: What is the value of b2 - 4ac for the following equation? x(x + 8) = 9

Weegy: x(x + 8) = 9; x^2 + 8x = 9; x^2 + 8x - 9 = 0 The value of b^2 - 4ac or the discriminant is: (8)^2 - 4(1)(-9) = 64 + 36 = 100 User: Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x2 - 7x + 2 = 0 Weegy: 7x + 1 User: Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x2 - 7x + 2 = 0 User: Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x^2 - 7x + 2 = 0 User: What is the value of b2 - 4ac for the following equation? 2x 2 - 2x - 1 = 0 User: What is the value of b2 - 4ac for the following equation? x 2 + 5x + 4 = 0 (More)

Question

Updated 3/19/2015 8:45:11 PM

1 Answer/Comment

yeswey

6x^2 - 7x + 2 = 0
a = 6, b = -7, c = 2
b^2 - 4ac = (-7)^2 - 4(6)(2) = 49 - 48 = 1
x = (7 ± sqrt 1)/12
= (7 ± 1)/12
x = 8/12 = 2/3 or
x = 6/12 = 1/2
The solution set for the equation 6x^2 - 7x + 2 = 0 is {2/3, 1/2}

Added 3/19/2015 8:45:08 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [3/20/2015 8:51:39 AM]

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?

(More)

Question

Updated 3/20/2015 7:40:45 AM

1 Answer/Comment

janezeshun

The x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5 is x = -2 .
x = -12/3*2 = -12/6 = -2

Added 3/20/2015 7:40:45 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 7:43:35 AM]

Solve this quadratic equation using the quadratic formula. 2x2 - 10x + 7 = 0

Weegy: 2x^2 - 10x + 7 = 0 2(x - 5/2)^2 - 25/2 + 7 = 0 2(x - 5/2)^2 = 11/2 (x - 5/2)^2 = 11/4 x - 5/2 = sqrt of 11/2 x = sqrt of 11/2 + 5/2 User: Solve this quadratic equation using the quadratic formula. 2x^2 - 10x + 7 = 0 User: Solve this quadratic equation using the quadratic formula. x2 - 6x + 6 = 0 User: Solve this quadratic equation using the quadratic formula. x^2 - 6x + 6 = 0 User: Solve this quadratic equation using the quadratic formula. x^2 - 6x + 6 = 0 User: If the quadratic formula is used to solve 2x 2 = 8x - 3, what are the solutions? Weegy: 8x^2 - 2x = 1; 8x^2 - 2x - 1= 0; (4x + 1)(2x - 1) = 0 (4x + 1) = 0; 4x = -1, x = -1/4 or (2x - 1) = 0; 2x = 1; x = 1/2 Solution set: {x = -1/4, x = 1/2} User: If the quadratic formula is used to solve 2x^2 = 8x - 3, what are the solutions? Weegy: 8x^2 - 2x = 1; 8x^2 - 2x - 1= 0; (4x + 1)(2x - 1) = 0 (4x + 1) = 0; 4x = -1, x = -1/4 or (2x - 1) = 0; 2x = 1; x = 1/2 Solution set: {x = -1/4, x = 1/2} User: If the quadratic formula is used to solve 2x 2 - 3x - 1 = 0, what are the solutions? Weegy: 2x^ 2 - 3x = 5 2x^2 - 3x - 5 = 0 (x + 1)(2x - 5) = 0 x = -1 or x = 5/2 User: If the quadratic formula is used to solve 2x^2 - 3x - 1 = 0, what are the solutions? Weegy: 2x^ 2 - 3x = 5 2x^2 - 3x - 5 = 0 (x + 1)(2x - 5) = 0 x = -1 or x = 5/2 User: An object is dropped off a building that is 144 feet tall. After how many seconds does the object hit the ground? (s = 16t^2) Weegy: 16t^2 = 144 Simplify, divide both sides by 16 t^2 = 9 t = 3 seconds User: If the quadratic formula is used to find the solution set of 3x^2 + 4x - 2 = 0, what is the result of substituting in the values? (More)

Question

Updated 3/19/2015 8:40:58 PM

3 Answers/Comments

yeswey

2x^2 = 8x - 3
2x^2 - 8x + 3 = 0
a = 2, b = -8, c = 3
b^2 - 4ac = (-8)^2 - 4(2)(3) = 64 - 24 = 40
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (8 ± sqrt 40)/4
= (8 ± 2 sqrt 10)/4
= (4 ± sqrt 10)/2

Added 3/19/2015 8:34:57 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 6:41:24 AM]

yeswey

2x^2 - 3x - 1 = 0
a = 2, b = -3, c = -1
b^2 - 4ac = (-3)^2 - 4(2)(-1) = 9 + 8 = 17
x = [-b ± sqrt (b^2 - 4ac)]/2a
= (3 ± sqrt 17)/4

Added 3/19/2015 8:38:26 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 6:41:59 AM]

yeswey

3x^2 + 4x - 2 = 0
a = 3, b = 4, c = -2
b^2 - 4ac = 4^2 - 4(3)(-2) = 16 + 24 = 40
x = (-4 ± sqrt 40)/6
= (-4 ± 2 sqrt 10)/6
= (-2 ± sqrt 10)/3

Added 3/19/2015 8:40:58 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 6:42:50 AM]

What is the radius of the circle whose equation is x^2 + y^2 = 9

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Question

Updated 3/19/2015 5:35:59 PM

1 Answer/Comment

yeswey

The radius of the circle whose equation is x^2 + y^2 = 9 is 3.

Added 3/19/2015 5:35:59 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [3/20/2015 8:53:56 AM]

Find the distance between the points (-5, 0) and (-4, 1).

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Question

Not Answered

Updated 3/19/2015 7:39:50 PM

5 Answers/Comments

yeswey

The distance between the points (-5, 0) and (-4, 1) is sqrt (1^2 + 1^2) = sqrt 2.

Added 3/19/2015 7:34:26 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 5:58:51 AM]

yeswey

2x(x - 1) = 3
2x^2 - 2x - 3 = 0
a = 2, b = -2, c = -3
b^2 - 4ac = (-2)^2 - 4(2)(-3) = 4 + 24 = 28
x = (2 ± sqrt 28)/4
= (2 ± 2 sqrt 7)/4
= (1 ± sqrt 7)/2

Added 3/19/2015 7:37:26 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 5:59:30 AM]

yeswey

x^2 + 5x + 1 = 0
a = 1, b = 5, c = 1
b^2 - 4ac = 5^2 - 4(1)(1) = 25 - 4 = 21
x = (-5 ± sqrt 21)/2

Added 3/19/2015 7:38:45 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [3/20/2015 5:59:53 AM]

yeswey

x^2 + x - 12 = 0 in factored form is (x + 4)(x - 3) = 0

Added 3/19/2015 7:39:10 PM

This answer has been confirmed as correct and helpful.