Write the equation of the given circle.
center (-2, -2)
radius of 6

Question

Asked 6/10/2013 9:25:18 AM

Updated 7/3/2014 8:41:11 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [7/3/2014 8:41:11 PM]

s

selymi|Points 10616|

Question

Asked 6/10/2013 9:25:18 AM

Updated 7/3/2014 8:41:11 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by yeswey [7/3/2014 8:41:11 PM]

Rating

3

The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.

Added 7/3/2014 8:40:56 PM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [7/4/2014 2:02:02 PM]

The equation of the circle whose center is at (3, 7) and whose radius is 6 is
(x + 3)² + (y + 7)² = 6
(x + 3)² + (y + 7)² = 36
(x - 3)² + (y - 7)² = 36

Question

Not Answered

Updated 7/3/2014 8:41:51 PM

1 Answer/Comment

Find the product of (5a - 7)(2a - 1)?

Question

Updated 1/28/2018 7:24:33 AM

1 Answer/Comment

(5a - 7)(2a - 1)

= 10a^2 - 5a - 14a + 7

= 10^2 - 19a + 7

= 10a^2 - 5a - 14a + 7

= 10^2 - 19a + 7

Added 1/28/2018 7:24:33 AM

This answer has been confirmed as correct and helpful.

Write the equation of the given circle.
center (3, 3)
radius of 2

Question

Not Answered

Updated 7/3/2014 8:40:00 PM

2 Answers/Comments

8y^2 + 6y + 1
User: 5y2 - 2y - 3
**Weegy:** (5y + 3)(y - 1) **User:** 7x2 - 9x - 10
**Weegy:** 5 - 2(-4)/9(-4) + (-4)(5) = -167/9 or -18 5/9 (-18.56) (More)

Question

Updated 6/5/2014 11:56:14 PM

2 Answers/Comments

8y^2 + 6y + 1 = (2y + 1)(4y + 1)

Added 6/5/2014 11:55:31 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/2/2014 1:13:56 PM]

7x^2 - 9x - 10 = (x - 2)(7x + 5)

Added 6/5/2014 11:56:14 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/2/2014 1:14:12 PM]

31,978,288

questions answered

There are no comments.