Factor as much as possible: x^2+x-12
Question
Updated 8/11/2014 1:59:07 AM
Edited by jeifunk [8/11/2014 1:59:07 AM]
s
Original conversation
User: Factor as much as possible: x^2+x-12

Weegy:
clb61289|Points 62|

User: Factor as much as possible 2x^2+6x+4

User: Factor as much as possible: x^2-100

Weegy: The answer would be (x+10)(x-10) thus by the FOIL method (First, Outside + Inside, Last) it would be x^2-10x+10x-100, or x^2 - 100.

Question
Updated 8/11/2014 1:59:07 AM
Edited by jeifunk [8/11/2014 1:59:07 AM]
Rating
3
The factor of x^2+x-12 is (x+4)(x-3).
x^2+x-12
=x^2+4x-3x-12
=(x+4)(x-3).
Confirmed by jeifunk [8/11/2014 1:58:09 AM], Rated good by jeifunk
3
The answer for 2x^2+6x+4 is 2 (x+1)(+2).
2x^2+6x+4
=2(x^2+3x+2)
=2(x^2+x+2x+2)
=2(x+1)(x+2).
Confirmed by jeifunk [8/11/2014 1:59:14 AM], Rated good by jeifunk

Questions asked by the same visitor
multiply 3x^2.4x^3
Weegy: 3x + 2y = 11, y = 4x - > 3x + 2(4x) = 11 - > 3x + 8x = 11 - > x = 11/11 = 1 User: multiply 3x^2 . 4x^3 Weegy: x=6 and y=-4. Thus x ranges from 0,6,12.... and y ranges from -3,-4,-5.... User: divide 3x^9/3x^3 Weegy: 9x^4. If you are satisfied with my answer, please click 'Good' on the ratings. Thank you! User: divide 3x^9/3x^3 Weegy: 9x^4. If you are satisfied with my answer, please click 'Good' on the ratings. Thank you! User: Find: (-5x)^2 Weegy: The answer is "-125x^3" User: Multiply and Simplify: (x + 2)(x + 1) Weegy: = x2 + 7x + 10 User: Factor out the largest possible common factor (the GCF) from: 15xyz+10xy^2 (More)
Question
Updated 6/17/2014 4:57:01 AM
3x^2 * 4x^3 = 12x^5
(-5x)^2

= (-5x)(-5x)

= 25x^2
3x^9/3x^3 = x^6
Confirmed by jeifunk [6/17/2014 5:11:05 AM]
(x + 2)(x + 1) = x^2 + x + 2x + 2 = x^2 + 3x + 2
Confirmed by jeifunk [6/17/2014 5:10:45 AM]
The GCF of 15xyz+10xy^2 is 5xy.
15xyz+10xy^2 = 5xy(3z + 2y)
Confirmed by jeifunk [6/17/2014 5:11:41 AM]
Factor as much as possible: x^2-100 (x - 100)(x + 1) (x + 10)(x + 10) (x - 10)(x - 10) (x - 10)(x + 10) User: Solve for x: x^2+3x+2=0
Weegy: Yes, anything times 0 equals zero. User: Solve for x: x^2+3x+2=0 x = -2 AND x = -3 x = -2 AND x = -1 x = 2 AND x = 1 No solutions Weegy: Can you clarify your question please? User: Simplify/Reduce the Algebraic Fraction: x^2+3x-4/x^2-16 Weegy: (x^(2)+3x-4)/(x^(2)-16) ((x+4)(x-1))/(x^(2)-16) ((x+4)(x-1))/((x-4)(x+4)) ( (x+4) (x-1))/((x-4) (x+4) ) (x-1)/(x-4) (More)
Question
Updated 8/11/2014 1:59:21 AM
The answer for x^2-100 is (x-10)(x+10 .
x^2-100
=x^2-10^2
=x^2-10x+10x-10^2
=(x-10)(x+10).
Confirmed by jeifunk [8/11/2014 2:18:55 AM], Rated good by jeifunk
The answer for x^2+3x+2=0 is x=-1 and x=-2.
x^2+3x+2=0
(x+1)(x+2)=0
x+1=0,x=-1
x+2=0,x=-2.
Confirmed by jeifunk [8/11/2014 2:20:13 AM], Rated good by jeifunk
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