Lines m and n are perpendicular. If the slope of m is zero, then the slope of n is

Question

Asked 1/9/2015 11:02:15 AM

Updated 1/10/2015 7:06:23 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by janezeshun [1/10/2015 7:04:43 AM]

s

Question

Asked 1/9/2015 11:02:15 AM

Updated 1/10/2015 7:06:23 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by janezeshun [1/10/2015 7:04:43 AM]

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Lines m and n are perpendicular. If the slope of m is zero, then the slope of n is undefined .

Added 1/10/2015 7:04:39 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 12:06:11 PM]

3

Line j passes through the points (0, 0) and (c, d). Line k passes through the points (0,0) and (-d, c). Lines j and k are perpendicular .

slope of j = (d - 0)/(c - 0) = d/c

slope of k = (c - 0)/(-d - 0) = -c/d

d/c*(-c/d) = -1 , so they are perpendicular .

slope of j = (d - 0)/(c - 0) = d/c

slope of k = (c - 0)/(-d - 0) = -c/d

d/c*(-c/d) = -1 , so they are perpendicular .

Added 1/10/2015 7:06:23 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 12:11:10 PM]

The coordinates G(7, 3), H(9, 0), I(5, -1) form a right triangle.
true or false

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Not Answered

Updated 1/10/2015 1:12:40 PM

1 Answer/Comment

The coordinates G(7, 3), H(9, 0), I(5, -1) form a right triangle. false

GH = sqrt (3^2 + 2^2) = sqrt 13

HI = sqrt (4^2 + 1^2) = sqrt 17

GI = sqrt (2^2 + 4^2) = sqrt 20

(Sqrt 13)^2 + (Sqrt 17)^2 = 13 + 17 = 30

GH = sqrt (3^2 + 2^2) = sqrt 13

HI = sqrt (4^2 + 1^2) = sqrt 17

GI = sqrt (2^2 + 4^2) = sqrt 20

(Sqrt 13)^2 + (Sqrt 17)^2 = 13 + 17 = 30

Added 1/10/2015 1:12:40 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 1:32:43 PM]

Find the length of the radius for this circle.
(x - 3)² + (y - 5)² = 8
User: Find the equation of the circle whose center and radius are given.
center ( 5, 6), radius = 3
**Weegy:** The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)? + (y - 1)? = 9. **User:** Find the coordinates of the midpoint of the segment whose endpoints are given.
W (-3, -7) and X (-8, -4)
**User:** Find the distance between these points.
A (5, 8), B(-3, 4)
AB =
**User:** Find the equation of the circle whose center and radius are given.
center (0, 8), radius = 8
**Weegy:** The equation of the circle whose center is (0, 8) and radius = 8 is x^2 + (y - 8)^2 = 64 **User:** Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of
(More)

Question

Updated 1/10/2015 7:09:33 AM

3 Answers/Comments

The length of the radius for this circle. (x - 3)² + (y - 5)² = 8 is2*2^1/2.

r^2 = 8

r = 8^1/2

r = 2*2^1/2

r^2 = 8

r = 8^1/2

r = 2*2^1/2

Added 1/10/2015 7:07:54 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 11:55:16 AM]

The equation of the circle whose center and radius are given. center ( 5, 6), radius = 3 is (x - 5)^2 + (y - 6)^2 = 9 .

Added 1/10/2015 7:08:27 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 11:55:49 AM]

Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of 2/3 .

Added 1/10/2015 7:09:33 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [1/10/2015 12:05:33 PM]

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