Combination circuits may have resistors in series or parallel with other resistors True or False

Combination circuits may have resistors in series or parallel with other resistors. TRUE.

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Combination circuits may have resistors in series or parallel with other resistors. TRUE.

Added 2/22/2023 7:56:35 PM

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The total resistance of a parallel circuit is the reciprocal of the sum of the reciprocals of the individual branches true or false **Weegy:** The total resistance of a parallel circuit is the reciprocal of the sum of the reciprocals of the individual [ branches.
TRUE.
] (More)

Question|Asked by Eddie ozil

Expert Answered

Updated 148 days ago|12/27/2023 10:23:41 AM

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The total resistance in a series circuit is the sum of all the resistance in the circuit. True or False **Weegy:** The total resistance in a series circuit is the sum of all the resistance in the circuit. [
FALSE.
] (More)

Question|Asked by Eddie ozil

Expert Answered

Updated 232 days ago|10/5/2023 12:27:39 AM

1 Answer/Comment

The total resistance in a series circuit is the sum of all the resistance in the circuit. TRUE.

Added 232 days ago|10/5/2023 12:27:34 AM

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The total power is the sum of the resistors' power. True or False

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Updated 2/22/2023 7:45:13 PM

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The total power is the sum of the resistors' power. TRUE.

Added 2/22/2023 7:45:13 PM

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In a series circuit voltage is the same across all resistors. true or false

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Updated 2/22/2023 5:43:28 PM

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In a series circuit voltage is the same across all resistors. FALSE

Added 2/22/2023 5:43:28 PM

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The easiest way to calculate the total resistance in a series/parallel circuit is to:
1)first, simplify into a parallel circuit
2)add all the values together
3)either A or B may be first
4)first, simplify into a series circuit

Question|Asked by Eddie ozil

Not Answered

Updated 2/22/2023 5:40:12 PM

1 Answer/Comment

The easiest way to calculate the total resistance in a series/parallel circuit is to: first, simplify into a parallel circuit or add all the values together.

Added 2/22/2023 5:40:12 PM

This answer has been confirmed as correct and helpful.

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