(y^4)^-2(2x^4y^-2)^3

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Asked 2/4/2009 4:19:23 PM

Updated 84 days ago|10/29/2025 8:21:03 AM

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User: (y^4)^-2(2x^4y^-2)^3

Weegy: y=x+4 divided by 4
Expert answered|cqueen|Points 236|Rating **** (+47 -5)

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Asked 2/4/2009 4:19:23 PM

Updated 84 days ago|10/29/2025 8:21:03 AM

1 Answer/Comment

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cruz30

Simplify: (y^4)^-2 (2x^4y^-2)^3
Simplify each part
(y^4)^-2 = y^-8
(2x^4y^-2)^3 = 2^3 * (x^4)^3 * (y^-2)^3 = 8x^12y^-6
Multiply them together
y^-8 * 8x^12y^-6 = 8x^12y^-14
Write with positive exponents
= 8x^12 / y^14
Answer:
8x^12 / y^14

Added 84 days ago|10/29/2025 8:20:57 AM

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