multiply (2x^2+4x+16) (3x-4)

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Asked 10/7/2009 5:43:02 PM

Updated 9/2/2014 7:53:07 PM

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Flagged by alfred123 [9/2/2014 7:53:04 PM]

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Expert answered|Heather71|Points 1265|

Question

Asked 10/7/2009 5:43:02 PM

Updated 9/2/2014 7:53:07 PM

2 Answers/Comments

This conversation has been flagged as incorrect.

Flagged by alfred123 [9/2/2014 7:53:04 PM]

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(2x^2 + 4x + 16) (3x - 4)

= 6x^3 - 8x^2 + 12x^2 - 16x + 48x - 64;

= 6x^3 + 4x^2 + 32x - 64

= 6x^3 - 8x^2 + 12x^2 - 16x + 48x - 64;

= 6x^3 + 4x^2 + 32x - 64

Added 9/2/2014 7:53:07 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [9/2/2014 8:25:53 PM]

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