HELLOW
Question
Asked 2/18/2009 5:39:25 PM
Updated 293 days ago|8/28/2023 12:11:49 AM
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Original conversation
User: A LENGHT OF WIRE IS DIVIDED BETWEEN TWO TEAMS IN THE RATIO 2:5.THE SECOND TEAM GETS 10 UNITS MORE WIRE THAN THE FIRST .HOW MUCH DOES THE FIRST TEAM GETS

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Expert answered|shanedunn138|Points 1238|Rating ***** (+239 -10)

Question
Asked 2/18/2009 5:39:25 PM
Updated 293 days ago|8/28/2023 12:11:49 AM
Rating
3
Let's assume that the first team gets 2x units of wire, and the second team gets 5x units of wire.

According to the given information, the second team gets 10 units more wire than the first team. So, we can set up an equation:

5x = 2x + 10

Now, solve for x:

5x - 2x = 10
3x = 10
x = 10 / 3

So, the first team gets 2x = 2 * (10 / 3) = 20 / 3 units of wire. This can also be expressed as approximately 6.67 units of wire.
Added 293 days ago|8/28/2023 12:11:49 AM
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