the present age of smita's mother is 3 times the age of smita. after 10 years the age of the mother will be twice the age of smita at that time. find their present ages.
Question|Rated good
Updated 151 days ago|7/8/2023 12:41:22 AM
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Original conversation
User: the present age of smita's mother is 3 times the age of smita. after 10 years the age of the mother will be twice the age of smita at that time. find their present ages.

Weegy: Smita is 10 years old and her mother is 30 years old.

User: Sum of the digits of atwo digit number is 12. The given number exceeds the number obtained by interchanging the digits by 36. find the given number. give with working.

Question|Rated good
Updated 151 days ago|7/8/2023 12:41:22 AM
Rating
3
Solution:
Let's denote Smita's present age as x. According to the problem, Smita's mother's present age is 3 times Smita's age, so we can express it as 3x.

After 10 years, Smita's age will be x + 10, and her mother's age will be 3x + 10.
3x + 10 = 2(x + 10)
3x + 10 = 2x + 20
3x - 2x = 20 - 10
x = 10

Therefore, Smita's present age is 10, and her mother's present age is 3 times that, which is 3 * 10 = 30.
Added 151 days ago|7/8/2023 12:39:03 AM
3
Solution:
Let's assume the two-digit number to be represented as 10a + b, where 'a' represents the tens digit and 'b' represents the units digit.

a + b = 12
10a + b = 10b + a + 36
10a - a = 10b - b + 36
9a = 9b + 36
a = b + 4
b + 4 + b = 12
2b + 4 = 12
2b = 12 - 4
2b = 8
b = 4

a + 4 = 12
a = 12 - 4
a = 8

Therefore, the tens digit 'a' is 8, and the units digit 'b' is 4. So, the two-digit number is 84.
Added 151 days ago|7/8/2023 12:41:22 AM

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