3
Using the point-slope form, we substitute the slope (m = 4) and the coordinates (x1 = 3, y1 = -5) into the equation:
y - y1 = m(x - x1)
y - (-5) = 4(x - 3)
y + 5 = 4(x - 3)
y + 5 = 4x - 12
y = 4x - 12 - 5
y = 4x - 17
Therefore, the equation for the line that is parallel to y = 4x + 6 and passes through the point (3, -5) is y = 4x - 17.
Added 5/26/2023 12:09:55 AM
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