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An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the two objects stick together. If the momentum is conserved, what is the new velocity of the combined object? Round to the nearest hundredth.
An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the two object stick together. If the momentum is conserved, the new velocity of the combined object is 18.60 m/s. Solution: Momentum=mass * velocity; P = m * v; 4000 = 115 * v; v=4000/115 =34.78 35m/s; Total mass = mass of initial object + mass of second object; Total mass = 115+100 = 215kg; v = p/m = 4000/215 = 18.60 m/s.
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Asked 7/10/2019 8:44:25 PM
Updated 10/11/2020 10:21:49 PM
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An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the two object stick together. If the momentum is conserved, the new velocity of the combined object is 18.60 m/s.
Solution:
Momentum=mass * velocity;
P = m * v;
4000 = 115 * v;
v=4000/115 =34.78 35m/s;
Total mass = mass of initial object + mass of second object;
Total mass = 115+100 = 215kg;
v = p/m = 4000/215 = 18.60 m/s.
Added 10/11/2020 10:21:49 PM
This answer has been confirmed as correct and helpful.
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