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(ab+cd)^2-(ac-bd)^2
Question
Asked 11/15/2008 11:40:37 AM
Updated 5/30/2014 5:40:15 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by andrewpallarca [5/30/2014 5:35:51 PM], Edited by andrewpallarca [5/30/2014 5:36:22 PM], Flagged by andrewpallarca [5/30/2014 5:40:15 PM]
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User: (ab+cd)^2-(ac-bd)^2

Weegy: A useful site to visit for algebra help is [www.algebrahelp.com/]



Question
Asked 11/15/2008 11:40:37 AM
Updated 5/30/2014 5:40:15 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by andrewpallarca [5/30/2014 5:35:51 PM], Edited by andrewpallarca [5/30/2014 5:36:22 PM], Flagged by andrewpallarca [5/30/2014 5:40:15 PM]
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(ab+cd)^2 - (ac-bd)^2;

(a^2b^2 + 2abcd + c^2d^2) - (a^2c^2 - 2abcd + b^2d^2)

= a^2b^2 - a^2c^2 + 4abcd - b^2d^2 + c^2d^2
Added 5/30/2014 5:40:14 PM
This answer has been confirmed as correct and helpful.
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8a3+27y3
Weegy: This is an equation with two variables. Do you have the other side of the equation? We need that to solve it. (More)
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Expert Answered
Updated 5/30/2014 5:35:33 PM
1 Answer/Comment
8a^3+27y^3 = (2a + 3y)(4a^2 - 6ay + 9y^2)
Added 5/30/2014 5:35:33 PM
This answer has been confirmed as correct and helpful.
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