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Question and answer
(ab+cd)^2-(ac-bd)^2
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Question
Asked 11/15/2008 11:40:37 AM
Updated 5/30/2014 5:40:15 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by
andrewpallarca
[5/30/2014 5:35:51 PM], Edited by
andrewpallarca
[5/30/2014 5:36:22 PM], Flagged by
andrewpallarca
[5/30/2014 5:40:15 PM]
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(ab+cd)^2-(ac-bd)^2
Original conversation
User:
(ab+cd)^2-(ac-bd)^2
Weegy:
A useful site to visit for algebra help is [
www.algebrahelp.com/
]
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Question
Asked 11/15/2008 11:40:37 AM
Updated 5/30/2014 5:40:15 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Edited by
andrewpallarca
[5/30/2014 5:35:51 PM], Edited by
andrewpallarca
[5/30/2014 5:36:22 PM], Flagged by
andrewpallarca
[5/30/2014 5:40:15 PM]
New answers
Rating
8
andrewpallarca
M
(ab+cd)^2 - (ac-bd)^2;
(a^2b^2 + 2abcd + c^2d^2) - (a^2c^2 - 2abcd + b^2d^2)
= a^2b^2 - a^2c^2 + 4abcd - b^2d^2 + c^2d^2
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Added 5/30/2014 5:40:14 PM
This answer has been confirmed as correct and helpful.
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Questions asked by the same visitor
8a3+27y3
Weegy:
This is an equation with two variables. Do you have the other side of the equation? We need that to solve it.
(More)
Question
Expert Answered
Updated 5/30/2014 5:35:33 PM
1 Answer/Comment
8
andrewpallarca
M
8a^3+27y^3 = (2a + 3y)(4a^2 - 6ay + 9y^2)
Added 5/30/2014 5:35:33 PM
This answer has been confirmed as correct and helpful.
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