What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)?

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Asked 3/8/2012 12:12:24 PM

Updated 7/28/2014 3:48:44 PM

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Flagged by jerry06 [7/28/2014 3:48:44 PM]

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Question

Asked 3/8/2012 12:12:24 PM

Updated 7/28/2014 3:48:44 PM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by jerry06 [7/28/2014 3:48:44 PM]

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The midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2) is (-10.5, 5). M = [(-8-13)/2, (12-2)/2]; M = (-21/2, 10/2); M = (-10.5, 5)

Added 7/28/2014 3:48:43 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/28/2014 3:51:53 PM]

What is the equation of a circle whose center is at the origin and whose radius is 9? **Weegy:** A. x^2 + y^2 = 3
B. x^2 + y^2 = 9
C. x^2 + y^2 = 81
**User:** The endpoints of the diameter of a circle are (-7, 3) and (5, 1). What is the center of the circle? **Weegy:** the center is (1, 2) **User:** What is the equation of a circle whose center is at the origin and whose radius is 9? (More)

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Updated 7/17/2014 12:09:55 AM

2 Answers/Comments

The endpoints of the diameter of a circle are (-7, 3) and (5, 1). The center of the circle is (-1, 2).

Added 7/17/2014 12:09:14 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/17/2014 12:39:53 AM]

The equation of a circle whose center is at the origin and whose radius is 9 is x^2 + y^2 = 81.

Added 7/17/2014 12:09:55 AM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/17/2014 12:40:05 AM]

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