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What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)?
Question
Asked 3/8/2012 12:12:24 PM
Updated 7/28/2014 3:48:44 PM
1 Answer/Comment
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Flagged by jerry06 [7/28/2014 3:48:44 PM]
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Original conversation
User: What is the midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2)?

Weegy: x + 3 = -5; x = -8
Clarkcj|Points 0|

User: What number is midway between and 1?

Question
Asked 3/8/2012 12:12:24 PM
Updated 7/28/2014 3:48:44 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jerry06 [7/28/2014 3:48:44 PM]
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The midpoint of the line segment whose endpoints are (-8, 12) and (-13, -2) is (-10.5, 5). M = [(-8-13)/2, (12-2)/2]; M = (-21/2, 10/2); M = (-10.5, 5)
Added 7/28/2014 3:48:43 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/28/2014 3:51:53 PM]
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Questions asked by the same visitor
What is the equation of a circle whose center is at the origin and whose radius is 9?
Weegy: A. x^2 + y^2 = 3 B. x^2 + y^2 = 9 C. x^2 + y^2 = 81 User: The endpoints of the diameter of a circle are (-7, 3) and (5, 1). What is the center of the circle? Weegy: the center is (1, 2) User: What is the equation of a circle whose center is at the origin and whose radius is 9? (More)
Question
Updated 7/17/2014 12:09:55 AM
2 Answers/Comments
The endpoints of the diameter of a circle are (-7, 3) and (5, 1). The center of the circle is (-1, 2).

Added 7/17/2014 12:09:14 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/17/2014 12:39:53 AM]
The equation of a circle whose center is at the origin and whose radius is 9 is x^2 + y^2 = 81.
Added 7/17/2014 12:09:55 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/17/2014 12:40:05 AM]
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