standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x

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standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x - 2y = 6

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Asked 10/18/2011 7:43:51 AM

Updated 10/25/2011 12:22:23 AM

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User: standard form the equation of the given line. The line that passes through (-2, 4) and is parallel to x - 2y = 6

Weegy: The answer is y=(x)/(2)+5. [ Here is the steps for solving such a problem: x-2y=6_(-2,4) Since x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting x from both sides. -2y=-x+6 Divide each term in the equation by -2. -(2y)/(-2)=-(x)/(-2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. -(-(2y)/(2))=-(x)/(-2)+(6)/(-2) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. -*-(2y)/(2)=-(x)/(-2)+(6)/(-2) Cancel the common factor of 2 in -(2y)/(2). -*( 2 y)/( 2 )=-(x)/(-2)+(6)/(-2) Remove the common factors that were cancelled out. -*-y=-(x)/(-2)+(6)/(-2) Multiply - by -y to get y. y=-(x)/(-2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. y=-(-(x)/(2))+(6)/(-2) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. y=-*-(x)/(2)+(6)/(-2) Multiply - by -x to get x. y=(x)/(2)+(6)/(-2) Move the minus sign from the denominator to the front of the expression. y=(x)/(2)-((6)/(2)) Multiply the factor by the rest of the expression to remove the fraction from the denominator. To multiply by a factor in the denominator, multiply by 1 over the factor. y=(x)/(2)-(6)/(2) Cancel the common factor of 2 in -(6)/(2). y=(x)/(2)-(^(3) 6 )/( 2 ) Remove the common factors that were cancelled out. y=(x)/(2)-3 To find the slope and y intercept, use the y=mx+b formula where m=slope and b is the y intercept. y=mx+b Using the y=mx+b formula, m=(1)/(2). m=(1)/(2) To find an equation that is parallel to x-2y=6, the slopes must be equal. ]
Expert answered|thederby|Points 70|

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Asked 10/18/2011 7:43:51 AM

Updated 10/25/2011 12:22:23 AM

3 Answers/Comments

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asero1010

y=(1/2)x+6 is the standard form equation of the line that passes through (-2, 4) and is parallel to x - 2y = 6.

Added 10/24/2011 12:27:23 PM

This answer has been confirmed as correct and helpful.

Confirmed by andrewpallarca [7/22/2014 4:01:26 PM]

thederby

How can you rate me bad when the answer is correct. What is would be the standard form...

Added 10/24/2011 8:22:27 PM

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asero1010

@thederby the standard form is y=mx+b so the correct equation should be y=(1/2)x+6, where m=1/2 and b=6. your answer y=(x)/(2)+5 is incorrect. the y-intercept "b" should be equal to 6 not 5. ref:

Added 10/25/2011 12:22:23 AM

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