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use the quadratic formula 2y^2-3y-6=0
2y^2 - 3y - 6 = 0 a = 2, b = -3, c = -6 b^2 - 4ac = (-3)^2 - 4(2)(-6) = 9 + 48 = 57 y = [-b ± sqrt (b^2 - 4ac)]/2a = (3 ± sqrt 57)/4
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Asked 4/6/2014 4:35:27 PM
Updated 7/8/2014 8:46:31 AM
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2y^2 - 3y - 6 = 0
a = 2, b = -3, c = -6
b^2 - 4ac = (-3)^2 - 4(2)(-6) = 9 + 48 = 57
y = [-b ± sqrt (b^2 - 4ac)]/2a
= (3 ± sqrt 57)/4
Added 7/8/2014 8:46:31 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/8/2014 8:50:46 AM]
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