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The equation of the circle whose center is at (3, 7) and whose radius is 6 is
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Asked 5/31/2013 7:33:16 PM
Updated 7/4/2014 2:29:20 AM
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Flagged by yeswey [7/4/2014 2:28:57 AM]
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User: The equation of the circle whose center is at (3, 7) and whose radius is 6 is

Weegy: First know the equation of a circle. (x-h)^2 + (y-k)^2 = r^2. Now it becomes easy. You plug in 5 for x and 6 for y. You plug in 3 for r. That will be your equation. (5-h)^2 + (6-k)^2 = 9.
drsyed19|Points 470|

User: The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 325 cubic inches and a length of 13 inches, what is the constant of proportionality for the group of boxes?

Weegy: 24 cubic inches
lailalayos|Points 190|

Question
Asked 5/31/2013 7:33:16 PM
Updated 7/4/2014 2:29:20 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/4/2014 2:28:57 AM]
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The equation of the circle whose center is at (3, 7) and whose radius is 6 is (x - 3)^2 + (y - 7)^2 = 36.
Added 7/4/2014 2:29:20 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [7/4/2014 3:01:20 PM]
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