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Expand (2x + 3)(x^2 - x - 5).
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Asked 12/11/2011 12:34:16 PM
Updated 7/22/2015 9:43:11 AM
1 Answer/Comment
Edited by Andrew. [7/22/2015 9:43:11 AM]
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User: Expand (2x + 3)(x^2 - x - 5).

Question
Asked 12/11/2011 12:34:16 PM
Updated 7/22/2015 9:43:11 AM
1 Answer/Comment
Edited by Andrew. [7/22/2015 9:43:11 AM]
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(2x + 3)(x^2 - x - 5) = 2x^3 - 2x^2 - 10x + 3x^2 - 3x - 15 = 2x^3 + x^2 - 13x - 15
Added 8/17/2014 6:22:06 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/17/2014 6:24:50 PM]
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A ______________ is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0
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Not Answered
Updated 8/17/2014 6:25:04 PM
1 Answer/Comment
A quadratic equation is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0.
Added 12/4/2011 6:34:54 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/17/2014 6:25:05 PM]
find x: 3(x-5)=0
Weegy: 3(x-5)=0; 3x - 15 = 0, 3x = 15, x = 15/3, x = 5 (More)
Question
Expert Answered
Updated 8/17/2014 6:25:55 PM
0 Answers/Comments
Solve: (6x^2+5x-1) ÷ (2x+1)
Weegy: (6x^2+5x-1) ÷ (2x+1) =((x+1)(6x-1))/(2x+1) (More)
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Expert Answered
Updated 12/5/2011 5:30:10 AM
6 Answers/Comments
My answer is not wrong. You can't flag it. Please, reconsider your question.
Added 12/4/2011 11:50:15 PM
The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
Added 12/5/2011 5:30:10 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/17/2014 6:29:44 PM]
Solve: (6x^2+5x-1) ÷ (2x+1)
Weegy: Is it a quadratic equation? User: No please divide the polynomials Weegy: 6x^2 + 2.5x+1 User: Sorr I dont understand your answer? (More)
Question
Expert Answered
Updated 12/5/2011 5:30:38 AM
1 Answer/Comment
The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
Added 12/5/2011 5:30:38 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/13/2014 6:31:03 PM]
I have a canker sores any remedies for this?
Weegy: Rinsing your mouth with salt water morning and night will help speed healing of canker sores. (More)
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Asked 12/4/2011 7:45:50 PM
0 Answers/Comments
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