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solution set for (x + 1)2 = 25
(x + 1)^2 = 25; x^2 + 2x + 1 = 25; x^2 + 2x - 24 = 0; (x + 6)(x - 4) = 0; x + 6 = 0; x = -6; x - 4 = 0; x = 4; x = {-6, 4}
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Asked 12/16/2015 4:33:06 PM
Updated 12/16/2015 4:51:39 PM
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(x + 1)^2 = 25;

x^2 + 2x + 1 = 25;

x^2 + 2x - 24 = 0;

(x + 6)(x - 4) = 0;

x + 6 = 0; x = -6;
x - 4 = 0; x = 4;

x = {-6, 4}

Added 12/16/2015 4:51:39 PM
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