semicircle
Question
Updated 9/25/2017 5:15:35 AM
This conversation has been flagged as incorrect.
Original conversation
User: semicircle

Weegy: Area formula for a semicircle: 1 Figure out the radius of the semicircle. 2 The area of the semi-circle is half the area of the corresponding circle. [ Hence, it is given by the formula:Area = [(pi)(r2)]/2 where, r is the radius of the semi-circle (or the circle) The area of a semicircle is (1/2)(pi)(r^2). The area of a circle is (pi)(r^2) ]
jeifunk|Points 42655|

User: sphere

Weegy: A sphere is a perfectly round geometrical object in three-dimensional space.

User: minor arc

Question
Updated 9/25/2017 5:15:35 AM
This conversation has been flagged as incorrect.
Rating
3
In mathematics (and more specifically geometry), a semicircle is a one-dimensional locus of points that forms half of a circle.
Confirmed by jeifunk [9/25/2017 5:46:36 AM]
3
A minor arc (left figure) is an arc of a circle having measure less than or equal to 180 degrees (pi radians).
Confirmed by jeifunk [9/25/2017 5:44:57 AM]

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Parallelogram
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Question
Updated 2/17/2015 11:10:56 AM
In Euclidean geometry, a parallelogram is a (non self-intersecting) quadrilateral with two pairs of parallel sides.
Confirmed by yumdrea [2/17/2015 11:11:03 AM]
In Euclidean geometry, a rhombus, plural rhombi or rhombuses, is a simple (non-self-intersecting) quadrilateral all of whose four sides have the same length.
Confirmed by yumdrea [2/17/2015 11:11:05 AM]
Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given. Center (8, 0), radius =
Weegy: In the standard equation of a circle, (x-a)^2 + (y-b)^2 = r^2, the center of the circle is (a, b) and the radius is r. User: Enter the equation of the line meeting the given conditions. Please put the equation in standard form. Containing C(3, 3) and D(-3, 2) Weegy: 1+-4=3 User: Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given. Center (7, 5), radius = 4 Weegy: The equation of the circle with Center (7, 5), radius = 4 in standard form is (x - 7)^2 + (y - 5)^2 = 16. User: Find the distance between the given points. W(0, 8) and X(0, 12) Distance = 4 4 (13) 10 Weegy: the answer to the equation 3(w+12)User: Find the distance between the given points. E(-6, 4) and F(-12, 4) Distance = 6 8 18 User: Enter the equation of the line meeting the given conditions. Please put the equation in standard form. Containing E(4, 3) and F(6, 1) (More)
Question
Updated 2/18/2015 3:38:26 PM
The equation of the line Containing C(3, 3) and D(-3, 2) in standard form is x -6y = -15
The distance between the given points W (0, 8) and X(0, 12) is distance = 4.
Confirmed by sujaysen [2/18/2015 3:36:19 PM]
The distance between the given points E(-6, 4) and F(-12, 4) is Distance = 6
Confirmed by sujaysen [2/18/2015 3:36:00 PM]
The equation of the line Containing E(4, 3) and F(6, 1) in standard form is x + y = 7
Enter the equation of the line meeting the given conditions. Please put the equation in standard form. Containing A(5, 3) and perpendicular to a line with slope of -2 User: Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given. Center (-8, -3), radius = 2 User: Find the distance between the given points. A(5, 3) and B(7, -4)
Weegy: -4|-4| = -4 * 4; = -16 User: Find the distance between the given points. R(0, 0) and S(6, 8) Distance = 2 7 (22) 10 Weegy: The answer is zero. The property is identity property of addition. This property states that any number plus 0 equals that number. [smile] User: Indicate the equation of the line meeting the given conditions. Please put the equation in standard form. Containing A(1, 3) and B(0, 2) (More)
Question
Updated 2/19/2015 4:47:20 PM
The equation of the circle in standard form with center (-8, -3), radius = 2 is (x + 8)^2 + (y + 3)^2 = 4.
Confirmed by Andrew. [2/19/2015 6:31:37 PM]
The distance between the given points A(5, 3) and B(7, -4) is sqrt (2^2 + 7^2) = sqrt 53
Confirmed by Andrew. [2/19/2015 6:32:30 PM]
The distance between the given points R(0, 0) and S(6, 8) is Distance = sqrt (6^2 + 8^2) = 10
Confirmed by Andrew. [2/19/2015 6:32:56 PM]
The equation of the line Containing A(1, 3) and B(0, 2) in standard form is x - y = -2
Confirmed by Andrew. [2/19/2015 6:33:27 PM]
Find the distance between the given points. A(5, 3) and B(7, -4) Distance =
Weegy: -4|-4| = -4 * 4; = - 16 User: Please put the equation in standard form. Containing E(4, 3) and F(6, 1) (More)
Question
Updated 2/20/2015 3:41:41 AM
The distance between the given points A (5 ,3) B (7 , -4) is sqrt of 53 .
distance^2 = (5 - 7)^2 + (3 + 4)^2
distance^2 = 4 + 49
distance^2 = 53
distance = sqrt of 53
Confirmed by sujaysen [2/20/2015 7:54:44 AM]
The equation in standar form that containning E (4 , 3), F (6 , 1) is x + y = 7 .
slope = (1 - 3)/(6 - 4) = -2/2 = -1
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7
x + y = 7
29,319,491
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