The vertex from of the equation of a parabola is y=7(x-3)2+4. . What is the standard form of the equation?

y=7(x-3)^2+4 y=7(x^2-6x+9)+4 y=7x^2-42x+63+4 y=7x^2-42x+67 which is the standard form of the equation.

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Question|Asked by ermajane

Asked 11/25/2014 7:49:42 PM

Updated 11/25/2014 9:46:58 PM

2 Answers/Comments

Rating

8

y=7(x-3)^2+4

y=7(x^2-6x+9)+4

y=7x^2-42x+63+4

y=7x^2-42x+67 which is the standard form of the equation.

y=7(x^2-6x+9)+4

y=7x^2-42x+63+4

y=7x^2-42x+67 which is the standard form of the equation.

Added 11/25/2014 9:45:43 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/25/2014 9:59:20 PM]

The vertex from of the equation of a parabola is y=2(x+3)^2-5. What is the standard form of the equation?

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Updated 11/29/2014 5:40:10 AM

1 Answer/Comment

y=2(x+3)^2-5

y=2(x^2+6x+9)-5

y=2x^2+12x+18-5

y=2x^2+12x+13 which is the standard form of the equation .

y=2(x^2+6x+9)-5

y=2x^2+12x+18-5

y=2x^2+12x+13 which is the standard form of the equation .

Added 11/29/2014 5:40:10 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [11/29/2014 6:09:41 AM]

Establishing rules that will help you stay focused is called: A integration B concentration C perception D self-discipline
**Weegy:** Establishing rules that will help you stay focused is called self-discipline. **User:** The vertex form of the equation of a parabola is y=4((x-2)squared-1.What is the standard form of the equation? (More)

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Expert Answered

Updated 11/25/2014 9:57:26 PM

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