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What is the equation of the line that passes through (4, -1) and (-2, 3)? 2x - 3y - 5 = 0 2x + 3y - 5 = 0 -2x + 3y - 5 = 0
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Asked 4/2/2014 3:15:19 PM
Updated 4/3/2014 8:06:05 AM
1 Answer/Comment
Flagged by yeswey [4/3/2014 8:05:14 AM]
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User: What is the equation of the line that passes through (4, -1) and (-2, 3)? 2x - 3y - 5 = 0 2x + 3y - 5 = 0 -2x + 3y - 5 = 0

Question
Asked 4/2/2014 3:15:19 PM
Updated 4/3/2014 8:06:05 AM
1 Answer/Comment
Flagged by yeswey [4/3/2014 8:05:14 AM]
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The equation of the line that passes through (4, -1) and (-2, 3) is: 2x + 3y - 5 = 0.

Added 4/3/2014 8:06:05 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/3/2014 8:15:05 AM]
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1 Answer/Comment
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1 Answer/Comment
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