What is the equation of the line that passes through (4, -1) and (-2, 3)? 2x - 3y - 5 = 0 2x + 3y - 5 = 0 -2x + 3y - 5 = 0
Question
Updated 4/3/2014 8:06:05 AM
Flagged by yeswey [4/3/2014 8:05:14 AM]
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Original conversation
User: What is the equation of the line that passes through (4, -1) and (-2, 3)? 2x - 3y - 5 = 0 2x + 3y - 5 = 0 -2x + 3y - 5 = 0

Question
Updated 4/3/2014 8:06:05 AM
Flagged by yeswey [4/3/2014 8:05:14 AM]
Rating
3
The equation of the line that passes through (4, -1) and (-2, 3) is: 2x + 3y - 5 = 0.

Confirmed by jeifunk [4/3/2014 8:15:05 AM]

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